QuestionMay 28, 2025

A -0.00325C charge q_(1) is placed 5.62 m from a second charge q_(2) The first charge is repelled with a 48900 N force. What is the value of q_(2) ? Include the sign of the charge (+or-) [?]C square

A -0.00325C charge q_(1) is placed 5.62 m from a second charge q_(2) The first charge is repelled with a 48900 N force. What is the value of q_(2) ? Include the sign of the charge (+or-) [?]C square
A -0.00325C charge q_(1) is placed 5.62
m from a second charge q_(2) The first
charge is repelled with a 48900 N
force. What is the value of q_(2) ? Include
the sign of the charge (+or-)
[?]C
square

Solution
4.4(304 votes)

Answer

q_2 = +0.001 \, \text{C} Explanation 1. Apply Coulomb's Law Use the formula F = k \frac{|q_1 q_2|}{r^2}, where k = 8.9875 \times 10^9 \, \text{N m}^2/\text{C}^2, F = 48900 \, \text{N}, q_1 = -0.00325 \, \text{C}, and r = 5.62 \, \text{m}. 2. Solve for q_2 Rearrange to find q_2: q_2 = \frac{F \cdot r^2}{k \cdot |q_1|}. Substitute values: q_2 = \frac{48900 \cdot (5.62)^2}{8.9875 \times 10^9 \cdot 0.00325}.

Explanation

1. Apply Coulomb's Law<br /> Use the formula $F = k \frac{|q_1 q_2|}{r^2}$, where $k = 8.9875 \times 10^9 \, \text{N m}^2/\text{C}^2$, $F = 48900 \, \text{N}$, $q_1 = -0.00325 \, \text{C}$, and $r = 5.62 \, \text{m}$.<br />2. Solve for $q_2$<br /> Rearrange to find $q_2$: $q_2 = \frac{F \cdot r^2}{k \cdot |q_1|}$.<br /> Substitute values: $q_2 = \frac{48900 \cdot (5.62)^2}{8.9875 \times 10^9 \cdot 0.00325}$.
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