QuestionMay 30, 2025

A baseball is tossed upward with an initial velocity of +36m/s rises to some high position, and then falls back down to be caught at its original release position. What is the value of its velocity 4 seconds after release? -36m/s -4m/s -10m/s/s 0m/s 4m/s +10m/s/s

A baseball is tossed upward with an initial velocity of +36m/s rises to some high position, and then falls back down to be caught at its original release position. What is the value of its velocity 4 seconds after release? -36m/s -4m/s -10m/s/s 0m/s 4m/s +10m/s/s
A baseball is tossed upward with an initial velocity of +36m/s rises to some high
position, and then falls back down to be caught at its original release position. What
is the value of its velocity 4 seconds after release?
-36m/s
-4m/s
-10m/s/s
0m/s
4m/s
+10m/s/s

Solution
4.3(220 votes)

Answer

-3.2 \, m/s Explanation 1. Identify the formula Use the formula for velocity under constant acceleration: v = u + at, where u is initial velocity, a is acceleration, and t is time. 2. Apply values Initial velocity u = 36 \, m/s, acceleration due to gravity a = -9.8 \, m/s^2, time t = 4 \, s. 3. Calculate final velocity Substitute into the formula: v = 36 + (-9.8) \times 4 = 36 - 39.2 = -3.2 \, m/s.

Explanation

1. Identify the formula<br /> Use the formula for velocity under constant acceleration: $v = u + at$, where $u$ is initial velocity, $a$ is acceleration, and $t$ is time.<br />2. Apply values<br /> Initial velocity $u = 36 \, m/s$, acceleration due to gravity $a = -9.8 \, m/s^2$, time $t = 4 \, s$.<br />3. Calculate final velocity<br /> Substitute into the formula: $v = 36 + (-9.8) \times 4 = 36 - 39.2 = -3.2 \, m/s$.
Click to rate:

Similar Questions