QuestionMay 20, 2025

The element Polonium 1-210 undergoes an alpha decay during a nuclear reaction.Which equation represents this nuclear reaction? (}_{84)^210Poarrow _(2)^4He+_(82)^210Pb (}_{84)^210Poarrow _(2)^4He+_(82)^206Pb C. (}_{84)^210Po+_(2)^4Hearrow _(86)^214Rn (}_{84)^210Po+_(2)^4Hearrow _(82)^206Pb

The element Polonium 1-210 undergoes an alpha decay during a nuclear reaction.Which equation represents this nuclear reaction? (}_{84)^210Poarrow _(2)^4He+_(82)^210Pb (}_{84)^210Poarrow _(2)^4He+_(82)^206Pb C. (}_{84)^210Po+_(2)^4Hearrow _(86)^214Rn (}_{84)^210Po+_(2)^4Hearrow _(82)^206Pb
The element Polonium 1-210 undergoes an alpha decay during a nuclear reaction.Which equation represents this nuclear reaction?
(}_{84)^210Poarrow _(2)^4He+_(82)^210Pb
(}_{84)^210Poarrow _(2)^4He+_(82)^206Pb
C. (}_{84)^210Po+_(2)^4Hearrow _(86)^214Rn
(}_{84)^210Po+_(2)^4Hearrow _(82)^206Pb

Solution
4.1(118 votes)

Answer

{}_{84}^{210}Po\rightarrow _{2}^{4}He+_{82}^{206}Pb Explanation 1. Identify Alpha Decay In alpha decay, an element emits an alpha particle ({}_{2}^{4}He), reducing its atomic number by 2 and mass number by 4. 2. Apply Alpha Decay to Polonium-210 For {}_{84}^{210}Po, subtract 2 from the atomic number (84) and 4 from the mass number (210): New element: Atomic number = 84 - 2 = 82, Mass number = 210 - 4 = 206. 3. Determine Resulting Element The resulting element is Lead ({Pb}) with atomic number 82 and mass number 206.

Explanation

1. Identify Alpha Decay<br /> In alpha decay, an element emits an alpha particle (${}_{2}^{4}He$), reducing its atomic number by 2 and mass number by 4.<br /><br />2. Apply Alpha Decay to Polonium-210<br /> For ${}_{84}^{210}Po$, subtract 2 from the atomic number (84) and 4 from the mass number (210): <br /> New element: Atomic number = $84 - 2 = 82$, Mass number = $210 - 4 = 206$.<br /><br />3. Determine Resulting Element<br /> The resulting element is Lead (${Pb}$) with atomic number 82 and mass number 206.
Click to rate:

Similar Questions