QuestionMay 25, 2025

Arace car accelerates unilformly from 20m/s to 40m/s in 10 seconds. Determine the acceleration of the car and the distance traveled. a=(v_(1)-v_(1))ftand(Delta x=v_(i)t+hat^2) a=2m/s^2 Delta x=210m a=4m/s^2 Delta x=300m s=8m/s^2 Delta s=600m a=2m^2 Delta x=300m

Arace car accelerates unilformly from 20m/s to 40m/s in 10 seconds. Determine the acceleration of the car and the distance traveled. a=(v_(1)-v_(1))ftand(Delta x=v_(i)t+hat^2) a=2m/s^2 Delta x=210m a=4m/s^2 Delta x=300m s=8m/s^2 Delta s=600m a=2m^2 Delta x=300m
Arace car accelerates unilformly from 20m/s to 40m/s
in 10 seconds. Determine the acceleration of the car and the distance traveled.
a=(v_(1)-v_(1))ftand(Delta x=v_(i)t+hat^2)
a=2m/s^2
Delta x=210m
a=4m/s^2
Delta x=300m
s=8m/s^2
Delta s=600m
a=2m^2
Delta x=300m

Solution
4.6(190 votes)

Answer

Acceleration: 2 \, \text{m/s}^2, Distance traveled: 300 \, \text{m} Explanation 1. Calculate Acceleration Use the formula for acceleration a = \frac{v_f - v_i}{t}, where v_f = 40 \, \text{m/s}, v_i = 20 \, \text{m/s}, and t = 10 \, \text{s}. Thus, a = \frac{40 - 20}{10} = 2 \, \text{m/s}^2. 2. Calculate Distance Traveled Use the formula \Delta x = v_i t + \frac{1}{2} a t^2, where v_i = 20 \, \text{m/s}, a = 2 \, \text{m/s}^2, and t = 10 \, \text{s}. Thus, \Delta x = 20 \times 10 + \frac{1}{2} \times 2 \times 10^2 = 200 + 100 = 300 \, \text{m}.

Explanation

1. Calculate Acceleration<br /> Use the formula for acceleration $a = \frac{v_f - v_i}{t}$, where $v_f = 40 \, \text{m/s}$, $v_i = 20 \, \text{m/s}$, and $t = 10 \, \text{s}$. Thus, $a = \frac{40 - 20}{10} = 2 \, \text{m/s}^2$.<br /><br />2. Calculate Distance Traveled<br /> Use the formula $\Delta x = v_i t + \frac{1}{2} a t^2$, where $v_i = 20 \, \text{m/s}$, $a = 2 \, \text{m/s}^2$, and $t = 10 \, \text{s}$. Thus, $\Delta x = 20 \times 10 + \frac{1}{2} \times 2 \times 10^2 = 200 + 100 = 300 \, \text{m}$.
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