QuestionFebruary 2, 2026

According to a health statistics center, the mean weight of a 20-10-29-year-old female is 156.5 pounds, with a standard deviation of 512 pounds, The mean weight of a 20-to 29-year-old male is 183.4 pounds, with a standard deviation of 40 O pounds. Who is relatively heavier: a 20-10-29 -year-old fomale who weighs 160 pounds or a 20-to-29-year-old male who weighs 185 pounds? The 2-score for the female is square . The z-scare for the male is square Thus, the square is relativoly heavier. (Round to two decimal places as needed.)

According to a health statistics center, the mean weight of a 20-10-29-year-old female is 156.5 pounds, with a standard deviation of 512 pounds, The mean weight of a 20-to 29-year-old male is 183.4 pounds, with a standard deviation of 40 O pounds. Who is relatively heavier: a 20-10-29 -year-old fomale who weighs 160 pounds or a 20-to-29-year-old male who weighs 185 pounds? The 2-score for the female is square . The z-scare for the male is square Thus, the square is relativoly heavier. (Round to two decimal places as needed.)
According to a health statistics center, the mean weight of a 20-10-29-year-old female is 156.5 pounds, with a
standard deviation of 512 pounds, The mean weight of a 20-to 29-year-old male is 183.4 pounds, with a
standard deviation of 40 O pounds. Who is relatively heavier: a 20-10-29 -year-old fomale who weighs 160
pounds or a 20-to-29-year-old male who weighs 185 pounds?
The 2-score for the female is square  . The z-scare for the male is square  Thus, the square  is relativoly heavier.
(Round to two decimal places as needed.)

Solution
4.3(300 votes)

Answer

The z-score for the female is 0.0068. The z-score for the male is 0.04. Thus, the male is relatively heavier. Explanation 1. Calculate the z-score for the female Use the formula **z = \frac{x - \mu}{\sigma}**. For the female: z = \frac{160 - 156.5}{512} = \frac{3.5}{512} \approx 0.0068. 2. Calculate the z-score for the male Use the formula **z = \frac{x - \mu}{\sigma}**. For the male: z = \frac{185 - 183.4}{40} = \frac{1.6}{40} = 0.04. 3. Compare the z-scores The z-score for the male (0.04) is greater than the z-score for the female (0.0068), indicating the male is relatively heavier.

Explanation

1. Calculate the z-score for the female<br /> Use the formula **$z = \frac{x - \mu}{\sigma}$**. For the female: $z = \frac{160 - 156.5}{512} = \frac{3.5}{512} \approx 0.0068$.<br /><br />2. Calculate the z-score for the male<br /> Use the formula **$z = \frac{x - \mu}{\sigma}$**. For the male: $z = \frac{185 - 183.4}{40} = \frac{1.6}{40} = 0.04$.<br /><br />3. Compare the z-scores<br /> The z-score for the male (0.04) is greater than the z-score for the female (0.0068), indicating the male is relatively heavier.
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