QuestionAugust 21, 2025

How many grams of copper(II) sulfate (CuSO_(4)(159.609g/mol)) are contained in 87,0 mL of a1.4M solution? C 1.9times 10^4g 199 2.6times 10^3g 2.69

How many grams of copper(II) sulfate (CuSO_(4)(159.609g/mol)) are contained in 87,0 mL of a1.4M solution? C 1.9times 10^4g 199 2.6times 10^3g 2.69
How many grams of copper(II) sulfate (CuSO_(4)(159.609g/mol))
are contained in 87,0 mL of a1.4M solution?
C 1.9times 10^4g
199
2.6times 10^3g
2.69

Solution
4.3(143 votes)

Answer

19.44 g Explanation 1. Calculate moles of solute Use the formula M = \frac{\text{moles}}{\text{volume in L}}. Convert 87.0 mL to liters: 87.0 \, \text{mL} = 0.087 \, \text{L}. Moles of CuSO_4 = 1.4 \, \text{mol/L} \times 0.087 \, \text{L} = 0.1218 \, \text{mol}. 2. Calculate grams of copper(II) sulfate Use the formula \text{grams} = \text{moles} \times \text{molar mass}. Grams of CuSO_4 = 0.1218 \, \text{mol} \times 159.609 \, \text{g/mol} = 19.44 \, \text{g}.

Explanation

1. Calculate moles of solute<br /> Use the formula $M = \frac{\text{moles}}{\text{volume in L}}$. Convert 87.0 mL to liters: $87.0 \, \text{mL} = 0.087 \, \text{L}$. Moles of $CuSO_4 = 1.4 \, \text{mol/L} \times 0.087 \, \text{L} = 0.1218 \, \text{mol}$.<br />2. Calculate grams of copper(II) sulfate<br /> Use the formula $\text{grams} = \text{moles} \times \text{molar mass}$. Grams of $CuSO_4 = 0.1218 \, \text{mol} \times 159.609 \, \text{g/mol} = 19.44 \, \text{g}$.
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