QuestionDecember 14, 2025

In this chemical reaction 6 moles of each of the reactants is combined 3Mg+N_(2)arrow Mg_(3)N_(2) How many moles of excess reagent will be left over? 250 words remaining square

In this chemical reaction 6 moles of each of the reactants is combined 3Mg+N_(2)arrow Mg_(3)N_(2) How many moles of excess reagent will be left over? 250 words remaining square
In this chemical reaction 6 moles of each of the reactants is combined 3Mg+N_(2)arrow Mg_(3)N_(2) How many moles of excess reagent will be left over? 250 words remaining square

Solution
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Answer

4 moles of N_2 will be left over. Explanation 1. Identify limiting reagent 3 moles Mg react with 1 mole N_2 to form 1 mole Mg_3N_2. For 6 moles of each, Mg needed for 6 moles N_2 is 3 \times 6 = 18 moles, but only 6 moles Mg are present. Mg is limiting. 2. Calculate amount of product formed 6 moles Mg \div 3 (stoichiometry) = 2 moles Mg_3N_2 produced. 3. Calculate N_2 consumed 2 moles Mg_3N_2 require 2 moles N_2 (1:1 ratio). 4. Calculate excess N_2 left Initial N_2 is 6 moles; 2 moles used; 6 - 2 = 4 moles remain.

Explanation

1. Identify limiting reagent<br /> 3 moles Mg react with 1 mole $N_2$ to form 1 mole $Mg_3N_2$. For 6 moles of each, Mg needed for 6 moles $N_2$ is $3 \times 6 = 18$ moles, but only 6 moles Mg are present. Mg is limiting.<br />2. Calculate amount of product formed<br /> $6$ moles Mg $\div 3$ (stoichiometry) $= 2$ moles $Mg_3N_2$ produced.<br />3. Calculate $N_2$ consumed<br /> $2$ moles $Mg_3N_2$ require $2$ moles $N_2$ ($1:1$ ratio).<br />4. Calculate excess $N_2$ left<br /> Initial $N_2$ is $6$ moles; $2$ moles used; $6 - 2 = 4$ moles remain.
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