QuestionJuly 26, 2025

A gas occupies 718 mL at a temperature of 28.36^circ C What is the volume of gas at 116.05^circ C assuming pressure did not change? Give your answer in L to the hundredths place. Do not put units in the answer space.

A gas occupies 718 mL at a temperature of 28.36^circ C What is the volume of gas at 116.05^circ C assuming pressure did not change? Give your answer in L to the hundredths place. Do not put units in the answer space.
A gas occupies 718 mL at a temperature of 28.36^circ C What is the volume of gas at 116.05^circ C
assuming pressure did not change?
Give your answer in L to the hundredths place. Do not put units in the answer space.

Solution
4.2(178 votes)

Answer

0.93 Explanation 1. Convert Temperatures to Kelvin T_1 = 28.36 + 273.15 = 301.51 \, K; T_2 = 116.05 + 273.15 = 389.20 \, K 2. Apply Charles's Law **Charles's Law**: \frac{V_1}{T_1} = \frac{V_2}{T_2}. Solve for V_2: V_2 = V_1 \times \frac{T_2}{T_1} 3. Calculate New Volume V_2 = 718 \, mL \times \frac{389.20}{301.51} = 926.14 \, mL = 0.92614 \, L

Explanation

1. Convert Temperatures to Kelvin<br /> $T_1 = 28.36 + 273.15 = 301.51 \, K$; $T_2 = 116.05 + 273.15 = 389.20 \, K$<br />2. Apply Charles's Law<br /> **Charles's Law**: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$. Solve for $V_2$: $V_2 = V_1 \times \frac{T_2}{T_1}$<br />3. Calculate New Volume<br /> $V_2 = 718 \, mL \times \frac{389.20}{301.51} = 926.14 \, mL = 0.92614 \, L$
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