QuestionJuly 14, 2025

In the following problem divide using long division State the quotient, q(x) and the remainder, r(x) (x^2+12x+35)div (x+7) (x^2+12x+35)div (x+7)=square +(square )/(x+7) (Simplify your answers. Do not factor. Use integers or fractions for any numbers in the expressions.)

In the following problem divide using long division State the quotient, q(x) and the remainder, r(x) (x^2+12x+35)div (x+7) (x^2+12x+35)div (x+7)=square +(square )/(x+7) (Simplify your answers. Do not factor. Use integers or fractions for any numbers in the expressions.)
In the following problem divide using long division State the quotient, q(x) and the remainder,
r(x)
(x^2+12x+35)div (x+7)
(x^2+12x+35)div (x+7)=square +(square )/(x+7)
(Simplify your answers. Do not factor. Use integers or fractions for any numbers in
the expressions.)

Solution
4.0(326 votes)

Answer

Quotient: q(x) = x + 5, Remainder: r(x) = 0 Explanation 1. Set up the division Divide x^2 by x to get the first term of the quotient, which is x. 2. Multiply and subtract Multiply (x+7) by x to get x^2 + 7x. Subtract this from x^2 + 12x + 35 to get 5x + 35. 3. Repeat division Divide 5x by x to get 5. 4. Multiply and subtract again Multiply (x+7) by 5 to get 5x + 35. Subtract this from 5x + 35 to get a remainder of 0.

Explanation

1. Set up the division<br /> Divide $x^2$ by $x$ to get the first term of the quotient, which is $x$.<br /><br />2. Multiply and subtract<br /> Multiply $(x+7)$ by $x$ to get $x^2 + 7x$. Subtract this from $x^2 + 12x + 35$ to get $5x + 35$.<br /><br />3. Repeat division<br /> Divide $5x$ by $x$ to get $5$. <br /><br />4. Multiply and subtract again<br /> Multiply $(x+7)$ by $5$ to get $5x + 35$. Subtract this from $5x + 35$ to get a remainder of $0$.
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