QuestionJune 5, 2025

1. What mass of water is needed to dissolve 34.8 g of CuSO_(4) in order to prepare a 0.521 m solution? square 2. What would the concentration of the solution in question 1 be in units of ppm?

1. What mass of water is needed to dissolve 34.8 g of CuSO_(4) in order to prepare a 0.521 m solution? square 2. What would the concentration of the solution in question 1 be in units of ppm?
1. What mass of water is needed to dissolve 34.8 g of CuSO_(4) in order to prepare
a 0.521 m solution?
square 
2. What would the concentration of the solution in question 1 be in units of
ppm?

Solution
4.4(209 votes)

Answer

1. Calculate moles of CuSO_{4} ### Molar mass of CuSO_{4} is approximately 159.61 g/mol. Moles = \frac{34.8 \, \text{g}}{159.61 \, \text{g/mol}}. ## Step2: Use molality formula ### Molality (m) = \frac{\text{moles of solute}}{\text{kg of solvent}}. Rearrange to find kg of solvent: kg of solvent = \frac{\text{moles of solute}}{0.521 \, \text{m}}. ## Step3: Convert kg to grams ### Multiply kg of solvent by 1000 to convert to grams. # Answer: ### Approximately 115.6 g of water # Explanation: ## Step1: Calculate total mass of solution ### Total mass = mass of solute + mass of solvent = 34.8 g + 115.6 g. ## Step2: Calculate concentration in ppm ### ppm = \frac{\text{mass of solute}}{\text{total mass of solution}} \times 10^6. # Answer: ### Approximately 233,000 ppm
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