QuestionAugust 1, 2025

Select the correct answer Susan makes a simple pendulum by attaching a rock to a piece of string that is 24.6 centimeters long. Then she swings it back and forth. What is the period of her simple pendulum? A. 1.32 seconds B. 0.99 seconds C. 9.81 seconds D. 2.43 seconds

Select the correct answer Susan makes a simple pendulum by attaching a rock to a piece of string that is 24.6 centimeters long. Then she swings it back and forth. What is the period of her simple pendulum? A. 1.32 seconds B. 0.99 seconds C. 9.81 seconds D. 2.43 seconds
Select the correct answer
Susan makes a simple pendulum by attaching a rock to a piece of string that is 24.6 centimeters long. Then she swings it back and forth. What is the
period of her simple pendulum?
A. 1.32 seconds
B. 0.99 seconds
C. 9.81 seconds
D. 2.43 seconds

Solution
4.0(256 votes)

Answer

B. 0.99 seconds Explanation 1. Convert Length to Meters The length of the pendulum is 24.6 cm, which is 0.246 meters. 2. Use the Formula for Period of a Simple Pendulum The period T of a simple pendulum is given by **T = 2\pi \sqrt{\frac{L}{g}}**, where L is the length and g is the acceleration due to gravity (approximately 9.81 m/s²). 3. Calculate the Period Substitute L = 0.246 m and g = 9.81 m/s² into the formula: T = 2\pi \sqrt{\frac{0.246}{9.81}} \approx 0.99 seconds.

Explanation

1. Convert Length to Meters<br /> The length of the pendulum is 24.6 cm, which is 0.246 meters.<br /><br />2. Use the Formula for Period of a Simple Pendulum<br /> The period $T$ of a simple pendulum is given by **$T = 2\pi \sqrt{\frac{L}{g}}$**, where $L$ is the length and $g$ is the acceleration due to gravity (approximately 9.81 m/s²).<br /><br />3. Calculate the Period<br /> Substitute $L = 0.246$ m and $g = 9.81$ m/s² into the formula:<br /> $T = 2\pi \sqrt{\frac{0.246}{9.81}} \approx 0.99$ seconds.
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