QuestionMay 26, 2025

Do 1. (Velocity)^wedge 2=2(Acceleration)(Distance) 1. Acar accelerates unformly from rest to a speed of 30m/s over a distance of 150 m. What is the acceleration of the can? 2m/s^2 3m/s^2 4m/s^2 5m/s^2

Do 1. (Velocity)^wedge 2=2(Acceleration)(Distance) 1. Acar accelerates unformly from rest to a speed of 30m/s over a distance of 150 m. What is the acceleration of the can? 2m/s^2 3m/s^2 4m/s^2 5m/s^2
Do 1.
(Velocity)^wedge 2=2(Acceleration)(Distance)
1. Acar accelerates unformly from rest to a speed of 30m/s over a distance of 150 m. What is
the acceleration of the can?
2m/s^2
3m/s^2
4m/s^2
5m/s^2

Solution
4.4(190 votes)

Answer

3 \, m/s^2 Explanation 1. Identify known values Initial velocity u = 0 \, m/s, final velocity v = 30 \, m/s, distance s = 150 \, m. 2. Use the formula for acceleration Apply **v^2 = u^2 + 2as**. Since u = 0, it simplifies to v^2 = 2as. 3. Solve for acceleration a Rearrange to find a: a = \frac{v^2}{2s} = \frac{(30)^2}{2 \times 150}. 4. Calculate the value a = \frac{900}{300} = 3 \, m/s^2.

Explanation

1. Identify known values<br /> Initial velocity $u = 0 \, m/s$, final velocity $v = 30 \, m/s$, distance $s = 150 \, m$.<br />2. Use the formula for acceleration<br /> Apply **$v^2 = u^2 + 2as$**. Since $u = 0$, it simplifies to $v^2 = 2as$.<br />3. Solve for acceleration $a$<br /> Rearrange to find $a$: $a = \frac{v^2}{2s} = \frac{(30)^2}{2 \times 150}$.<br />4. Calculate the value<br /> $a = \frac{900}{300} = 3 \, m/s^2$.
Click to rate:

Similar Questions