QuestionMay 22, 2025

33. What is the current in a 240 V circuit that has 45kOmega of total resistance? 53.3 A 533 mA 5.33times 10^-2A 5.3times 10^-3A

33. What is the current in a 240 V circuit that has 45kOmega of total resistance? 53.3 A 533 mA 5.33times 10^-2A 5.3times 10^-3A
33. What is the current in a 240 V circuit that has 45kOmega  of total resistance?
53.3 A
533 mA
5.33times 10^-2A
5.3times 10^-3A

Solution
4.2(225 votes)

Answer

5.33\times 10^{-3}A Explanation 1. Identify the formula Use Ohm's Law: **I = \frac{V}{R}** where I is current, V is voltage, and R is resistance. 2. Substitute values Substitute V = 240 \, V and R = 45,000 \, \Omega into the formula: I = \frac{240}{45000}. 3. Calculate the current Perform the division: I = \frac{240}{45000} = 0.00533 \, A.

Explanation

1. Identify the formula<br /> Use Ohm's Law: **$I = \frac{V}{R}$** where $I$ is current, $V$ is voltage, and $R$ is resistance.<br /><br />2. Substitute values<br /> Substitute $V = 240 \, V$ and $R = 45,000 \, \Omega$ into the formula: $I = \frac{240}{45000}$.<br /><br />3. Calculate the current<br /> Perform the division: $I = \frac{240}{45000} = 0.00533 \, A$.
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