QuestionJuly 15, 2025

Solve the system and find the value of y. 2x+3y=1 5x-4y=-32 y= square

Solve the system and find the value of y. 2x+3y=1 5x-4y=-32 y= square
Solve the system and find the value of y.
2x+3y=1
5x-4y=-32
y=
square

Solution
4.3(302 votes)

Answer

y = 3 Explanation 1. Solve for x using elimination Multiply the first equation by 4 and the second by 3 to eliminate y: 8x + 12y = 4 and 15x - 12y = -96. 2. Add equations Add the modified equations: 23x = -92. 3. Calculate x Divide by 23: x = -4. 4. Substitute x into the first equation Substitute x = -4 into 2x + 3y = 1: 2(-4) + 3y = 1. 5. Solve for y Simplify: -8 + 3y = 1. Add 8 to both sides: 3y = 9. Divide by 3: y = 3.

Explanation

1. Solve for x using elimination<br /> Multiply the first equation by 4 and the second by 3 to eliminate y: $8x + 12y = 4$ and $15x - 12y = -96$.<br />2. Add equations<br /> Add the modified equations: $23x = -92$.<br />3. Calculate x<br /> Divide by 23: $x = -4$.<br />4. Substitute x into the first equation<br /> Substitute $x = -4$ into $2x + 3y = 1$: $2(-4) + 3y = 1$.<br />5. Solve for y<br /> Simplify: $-8 + 3y = 1$. Add 8 to both sides: $3y = 9$. Divide by 3: $y = 3$.
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