QuestionAugust 27, 2025

Which shows the correct substitution of the values a,b,and c from the equation -2=-x+x^2-4 into the quadratic formula? Quadratic formula: x=(-bpm sqrt (b^2-4ac))/(2a) x=(-(-1)pm sqrt ((-1)^2-4(1)(-4)))/(2(1)) x=(-1pm sqrt (1^2-4(-1)(-4)))/(2(-1)) x=(-1pm sqrt ((1)^2-4(-1)(-2)))/(2(-1)) x=(-(-1)pm sqrt ((-1)^2-4(1)(-2)))/(2(1))

Which shows the correct substitution of the values a,b,and c from the equation -2=-x+x^2-4 into the quadratic formula? Quadratic formula: x=(-bpm sqrt (b^2-4ac))/(2a) x=(-(-1)pm sqrt ((-1)^2-4(1)(-4)))/(2(1)) x=(-1pm sqrt (1^2-4(-1)(-4)))/(2(-1)) x=(-1pm sqrt ((1)^2-4(-1)(-2)))/(2(-1)) x=(-(-1)pm sqrt ((-1)^2-4(1)(-2)))/(2(1))
Which shows the correct substitution of the values a,b,and c from the equation -2=-x+x^2-4 into the quadratic
formula?
Quadratic formula: x=(-bpm sqrt (b^2-4ac))/(2a)
x=(-(-1)pm sqrt ((-1)^2-4(1)(-4)))/(2(1))
x=(-1pm sqrt (1^2-4(-1)(-4)))/(2(-1))
x=(-1pm sqrt ((1)^2-4(-1)(-2)))/(2(-1))
x=(-(-1)pm sqrt ((-1)^2-4(1)(-2)))/(2(1))

Solution
4.7(278 votes)

Answer

x=\frac {-(-1)\pm \sqrt {(-1)^{2}-4(1)(-4)}}{2(1)} Explanation 1. Identify coefficients Rewrite the equation as x^2 - x - 4 = 0. Here, a = 1, b = -1, and c = -4. 2. Substitute into quadratic formula Use the quadratic formula x=\frac {-b\pm \sqrt {b^{2}-4ac}}{2a} with a = 1, b = -1, c = -4.

Explanation

1. Identify coefficients<br /> Rewrite the equation as $x^2 - x - 4 = 0$. Here, $a = 1$, $b = -1$, and $c = -4$.<br />2. Substitute into quadratic formula<br /> Use the quadratic formula $x=\frac {-b\pm \sqrt {b^{2}-4ac}}{2a}$ with $a = 1$, $b = -1$, $c = -4$.
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