QuestionMay 19, 2026

5. How can 100. mL of sodium hydroxide solution with a pH of 13.00 be converted to a sodium hydroxide solution with a pH of 12.00 ? (A) By diluting the solution with distilled water to a total volume of 200 mL (B) By diluting the solution with distilled water to a total volume of 1.00 L (C) By adding 100 mL of 0.10 MHCI (D) By adding 100 mL of 0.10 MNaOH

5. How can 100. mL of sodium hydroxide solution with a pH of 13.00 be converted to a sodium hydroxide solution with a pH of 12.00 ? (A) By diluting the solution with distilled water to a total volume of 200 mL (B) By diluting the solution with distilled water to a total volume of 1.00 L (C) By adding 100 mL of 0.10 MHCI (D) By adding 100 mL of 0.10 MNaOH
5. How can 100. mL of sodium hydroxide solution with a pH of 13.00 be converted to a sodium hydroxide solution with a pH of 12.00 ? (A) By diluting the solution with distilled water to a total volume of 200 mL (B) By diluting the solution with distilled water to a total volume of 1.00 L (C) By adding 100 mL of 0.10 MHCI (D) By adding 100 mL of 0.10 MNaOH

Solution
4.4(186 votes)

Answer

(B) By diluting the solution with distilled water to a total volume of 1.00 L Explanation 1. Convert pH to pOH pOH = 14 - pH → For initial pH 13.00: pOH = 1.00. For target pH 12.00: pOH = 2.00. 2. Find [OH⁻] concentrations **[OH^-] = 10^{-pOH}** → Initial: [OH^-] = 10^{-1} = 0.10 \text{ M}; Target: [OH^-] = 10^{-2} = 0.010 \text{ M}. 3. Apply dilution formula **M_1 V_1 = M_2 V_2** → (0.10)(100\ \text{mL}) = (0.010) V_2 \rightarrow V_2 = 1000\ \text{mL}. 4. Interpret result Need total volume 1000\ \text{mL}, starting with 100\ \text{mL} means add 900\ \text{mL} of water → total = 1.00 L.

Explanation

1. Convert pH to pOH <br /> $pOH = 14 - pH$ → For initial pH $13.00$: $pOH = 1.00$. For target pH $12.00$: $pOH = 2.00$. <br /><br />2. Find [OH⁻] concentrations <br /> **$[OH^-] = 10^{-pOH}$** → Initial: $[OH^-] = 10^{-1} = 0.10 \text{ M}$; Target: $[OH^-] = 10^{-2} = 0.010 \text{ M}$. <br /><br />3. Apply dilution formula <br /> **$M_1 V_1 = M_2 V_2$** → $(0.10)(100\ \text{mL}) = (0.010) V_2 \rightarrow V_2 = 1000\ \text{mL}$. <br /><br />4. Interpret result <br /> Need total volume $1000\ \text{mL}$, starting with $100\ \text{mL}$ means add $900\ \text{mL}$ of water → total = $1.00$ L.
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