QuestionJune 27, 2025

A soccer player runs up behind a soccer ball (of mass 0.50 kg) that is moving at 3.5m/s in the same direction as the player. The soccer player kicks it and the ball moves with a speed of 13.5m/s What is the magnitude of the impulse (in kgm/s) delivered to the soccer ball? A 5.0 B 7.5 C 10 D 15

A soccer player runs up behind a soccer ball (of mass 0.50 kg) that is moving at 3.5m/s in the same direction as the player. The soccer player kicks it and the ball moves with a speed of 13.5m/s What is the magnitude of the impulse (in kgm/s) delivered to the soccer ball? A 5.0 B 7.5 C 10 D 15
A soccer player runs up behind a soccer ball (of mass 0.50 kg) that is moving at 3.5m/s in the same direction as the player. The soccer player kicks it and the ball moves with a speed of 13.5m/s What is the magnitude of the impulse (in kgm/s) delivered to the soccer ball? A 5.0 B 7.5 C 10 D 15

Solution
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Answer

A 5.0 Explanation 1. Identify initial and final velocities Initial velocity v_i = 3.5 \, \text{m/s}, final velocity v_f = 13.5 \, \text{m/s}. 2. Calculate change in velocity Change in velocity \Delta v = v_f - v_i = 13.5 - 3.5 = 10 \, \text{m/s}. 3. Apply impulse formula **Impulse** J = m \cdot \Delta v, where m = 0.50 \, \text{kg}. J = 0.50 \times 10 = 5.0 \, \text{kg m/s}.

Explanation

1. Identify initial and final velocities<br /> Initial velocity $v_i = 3.5 \, \text{m/s}$, final velocity $v_f = 13.5 \, \text{m/s}$.<br />2. Calculate change in velocity<br /> Change in velocity $\Delta v = v_f - v_i = 13.5 - 3.5 = 10 \, \text{m/s}$.<br />3. Apply impulse formula<br /> **Impulse** $J = m \cdot \Delta v$, where $m = 0.50 \, \text{kg}$.<br /> $J = 0.50 \times 10 = 5.0 \, \text{kg m/s}$.
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