QuestionJuly 23, 2025

3. Three beakers contain different volumes of water of 8.1cm^3 0.64 L, and 2.7 dL. If all three volumes were mixed together in a larger container, what would the final volume in mL be?

3. Three beakers contain different volumes of water of 8.1cm^3 0.64 L, and 2.7 dL. If all three volumes were mixed together in a larger container, what would the final volume in mL be?
3. Three beakers contain different volumes of water of 8.1cm^3 0.64 L, and 2.7 dL. If all three volumes were mixed together in a larger container, what would the final volume in mL be?

Solution
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Answer

918.1 mL Explanation 1. Convert all volumes to mL 8.1 \, \text{cm}^3 = 8.1 \, \text{mL} (since 1 \, \text{cm}^3 = 1 \, \text{mL}). 0.64 \, \text{L} = 640 \, \text{mL} (since 1 \, \text{L} = 1000 \, \text{mL}). 2.7 \, \text{dL} = 270 \, \text{mL} (since 1 \, \text{dL} = 100 \, \text{mL}). 2. Sum the volumes Add the converted volumes: 8.1 \, \text{mL} + 640 \, \text{mL} + 270 \, \text{mL} = 918.1 \, \text{mL}.

Explanation

1. Convert all volumes to mL<br /> $8.1 \, \text{cm}^3 = 8.1 \, \text{mL}$ (since $1 \, \text{cm}^3 = 1 \, \text{mL}$).<br /> $0.64 \, \text{L} = 640 \, \text{mL}$ (since $1 \, \text{L} = 1000 \, \text{mL}$).<br /> $2.7 \, \text{dL} = 270 \, \text{mL}$ (since $1 \, \text{dL} = 100 \, \text{mL}$).<br /><br />2. Sum the volumes<br /> Add the converted volumes: $8.1 \, \text{mL} + 640 \, \text{mL} + 270 \, \text{mL} = 918.1 \, \text{mL}$.
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