QuestionJuly 20, 2025

Depth of Gate=2cm PRP=26mu s (2cmtimes 13mu s) PRF=38.5kHz(77,000(cm)/(s)div 2cm=38,500Hz) NL=19.25kHz((38.5kHz)/(2))

Depth of Gate=2cm PRP=26mu s (2cmtimes 13mu s) PRF=38.5kHz(77,000(cm)/(s)div 2cm=38,500Hz) NL=19.25kHz((38.5kHz)/(2))
Depth of Gate=2cm PRP=26mu s (2cmtimes 13mu s) PRF=38.5kHz(77,000(cm)/(s)div 2cm=38,500Hz) NL=19.25kHz((38.5kHz)/(2))

Solution
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Answer

PRP = 26 μs, PRF = 38,500 Hz, NL = 19,250 Hz Explanation 1. Calculate Pulse Repetition Period (PRP) Given depth of gate is 2 cm, and PRP is calculated as 2 \text{ cm} \times 13 \mu s/\text{cm} = 26 \mu s. 2. Calculate Pulse Repetition Frequency (PRF) PRF is calculated using the formula \text{PRF} = \frac{\text{Speed of sound}}{\text{Depth}}. Given speed of sound is 77,000 cm/s, so \text{PRF} = \frac{77,000 \text{ cm/s}}{2 \text{ cm}} = 38,500 \text{ Hz}. 3. Calculate Nyquist Limit (NL) NL is half of PRF. So, \text{NL} = \frac{38,500 \text{ Hz}}{2} = 19,250 \text{ Hz}.

Explanation

1. Calculate Pulse Repetition Period (PRP)<br /> Given depth of gate is 2 cm, and PRP is calculated as $2 \text{ cm} \times 13 \mu s/\text{cm} = 26 \mu s$.<br /><br />2. Calculate Pulse Repetition Frequency (PRF)<br /> PRF is calculated using the formula $\text{PRF} = \frac{\text{Speed of sound}}{\text{Depth}}$. Given speed of sound is 77,000 cm/s, so $\text{PRF} = \frac{77,000 \text{ cm/s}}{2 \text{ cm}} = 38,500 \text{ Hz}$.<br /><br />3. Calculate Nyquist Limit (NL)<br /> NL is half of PRF. So, $\text{NL} = \frac{38,500 \text{ Hz}}{2} = 19,250 \text{ Hz}$.
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