QuestionAugust 23, 2025

At a particular temperature, the equilibrium constant for the reaction below is K_(c)=4.01 H_(2)(g)+Cl_(2)(g)leftharpoons 2HCl(g) What is the equilibrium constant for the following reaction? 4HCl(g)leftharpoons 2H_(2)(g)+2Cl_(2)(g) 5.66 0.125 16.1 0.0622 8.02

At a particular temperature, the equilibrium constant for the reaction below is K_(c)=4.01 H_(2)(g)+Cl_(2)(g)leftharpoons 2HCl(g) What is the equilibrium constant for the following reaction? 4HCl(g)leftharpoons 2H_(2)(g)+2Cl_(2)(g) 5.66 0.125 16.1 0.0622 8.02
At a particular temperature, the equilibrium constant for the
reaction below is K_(c)=4.01
H_(2)(g)+Cl_(2)(g)leftharpoons 2HCl(g)
What is the equilibrium constant for the following reaction?
4HCl(g)leftharpoons 2H_(2)(g)+2Cl_(2)(g)
5.66
0.125
16.1
0.0622
8.02

Solution
4.6(147 votes)

Answer

0.0622 Explanation 1. Identify the relationship between reactions The given reaction is the reverse of the original and multiplied by 2. 2. Calculate the new equilibrium constant For reversing a reaction, use K' = \frac{1}{K}. For multiplying coefficients by n, use K'' = K'^n.

Explanation

1. Identify the relationship between reactions<br /> The given reaction is the reverse of the original and multiplied by 2.<br />2. Calculate the new equilibrium constant<br /> For reversing a reaction, use $K' = \frac{1}{K}$. For multiplying coefficients by n, use $K'' = K'^n$.
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