QuestionAugust 26, 2025

b) -16=-(15)/(16)((4)/(5) q+(32)/(3))

b) -16=-(15)/(16)((4)/(5) q+(32)/(3))
b) -16=-(15)/(16)((4)/(5) q+(32)/(3))

Solution
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Answer

( q = 8 ) Explanation 1. Simplify the equation Multiply both sides by -\frac{16}{15} to eliminate the fraction: \[ -16 \times -\frac{16}{15} = \left(\frac{4}{5} q + \frac{32}{3}\right) \] 2. Calculate the left side Compute the multiplication: \[ \frac{256}{15} = \frac{4}{5} q + \frac{32}{3} \] 3. Eliminate the constant term Subtract \frac{32}{3} from both sides: \[ \frac{256}{15} - \frac{32}{3} = \frac{4}{5} q \] 4. Find a common denominator and simplify Convert fractions to have a common denominator (15): \[ \frac{256}{15} - \frac{160}{15} = \frac{96}{15} = \frac{4}{5} q \] 5. Solve for ( q ) Multiply both sides by \frac{5}{4} to solve for ( q ): \[ q = \frac{96}{15} \times \frac{5}{4} \] 6. Simplify the expression Perform the multiplication and simplification: \[ q = \frac{480}{60} = 8 \]

Explanation

1. Simplify the equation<br /> Multiply both sides by $-\frac{16}{15}$ to eliminate the fraction: <br />\[ -16 \times -\frac{16}{15} = \left(\frac{4}{5} q + \frac{32}{3}\right) \]<br /><br />2. Calculate the left side<br /> Compute the multiplication:<br />\[ \frac{256}{15} = \frac{4}{5} q + \frac{32}{3} \]<br /><br />3. Eliminate the constant term<br /> Subtract $\frac{32}{3}$ from both sides:<br />\[ \frac{256}{15} - \frac{32}{3} = \frac{4}{5} q \]<br /><br />4. Find a common denominator and simplify<br /> Convert fractions to have a common denominator (15):<br />\[ \frac{256}{15} - \frac{160}{15} = \frac{96}{15} = \frac{4}{5} q \]<br /><br />5. Solve for ( q )<br /> Multiply both sides by $\frac{5}{4}$ to solve for ( q ):<br />\[ q = \frac{96}{15} \times \frac{5}{4} \]<br /><br />6. Simplify the expression<br /> Perform the multiplication and simplification:<br />\[ q = \frac{480}{60} = 8 \]
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