QuestionAugust 21, 2025

How many grams of PbSO_(4) would be produced from the complete reaction of 23.6gPbO_(2) ? Pb+PbO_(2)+2H_(2)SO_(4)arrow 2PbSO_(4)+2H_(2)O PbO_(2):239.2g/mol PbSO_(4):303.27g/mol [?]gPbSO_(4)

How many grams of PbSO_(4) would be produced from the complete reaction of 23.6gPbO_(2) ? Pb+PbO_(2)+2H_(2)SO_(4)arrow 2PbSO_(4)+2H_(2)O PbO_(2):239.2g/mol PbSO_(4):303.27g/mol [?]gPbSO_(4)
How many grams of PbSO_(4) would
be produced from the complete
reaction of 23.6gPbO_(2) ?
Pb+PbO_(2)+2H_(2)SO_(4)arrow 
2PbSO_(4)+2H_(2)O
PbO_(2):239.2g/mol
PbSO_(4):303.27g/mol
[?]gPbSO_(4)

Solution
4.6(205 votes)

Answer

29.92 \, \text{g} \, \mathrm{PbSO}_{4} Explanation 1. Calculate moles of \( \mathrm{PbO}_{2} \) Use the formula: **moles = \(\frac{\text{mass}}{\text{molar mass}}\)**. Moles of \( \mathrm{PbO}_{2} = \frac{23.6 \, \text{g}}{239.2 \, \text{g/mol}} = 0.0987 \, \text{mol} \). 2. Determine moles of \( \mathrm{PbSO}_{4} \) produced From the balanced equation, 1 mole of \( \mathrm{PbO}_{2} \) produces 1 mole of \( \mathrm{PbSO}_{4} \). Thus, moles of \( \mathrm{PbSO}_{4} = 0.0987 \, \text{mol} \). 3. Calculate mass of \( \mathrm{PbSO}_{4} \) Use the formula: **mass = moles \(\times\) molar mass**. Mass of \( \mathrm{PbSO}_{4} = 0.0987 \, \text{mol} \times 303.27 \, \text{g/mol} = 29.92 \, \text{g} \).

Explanation

1. Calculate moles of \( \mathrm{PbO}_{2} \)<br /> Use the formula: **moles = \(\frac{\text{mass}}{\text{molar mass}}\)**. Moles of \( \mathrm{PbO}_{2} = \frac{23.6 \, \text{g}}{239.2 \, \text{g/mol}} = 0.0987 \, \text{mol} \).<br />2. Determine moles of \( \mathrm{PbSO}_{4} \) produced<br /> From the balanced equation, 1 mole of \( \mathrm{PbO}_{2} \) produces 1 mole of \( \mathrm{PbSO}_{4} \). Thus, moles of \( \mathrm{PbSO}_{4} = 0.0987 \, \text{mol} \).<br />3. Calculate mass of \( \mathrm{PbSO}_{4} \)<br /> Use the formula: **mass = moles \(\times\) molar mass**. Mass of \( \mathrm{PbSO}_{4} = 0.0987 \, \text{mol} \times 303.27 \, \text{g/mol} = 29.92 \, \text{g} \).
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