QuestionJuly 14, 2025

Zn(OH)_(2) has a K_(sp) of 4.5times 10^-17 If you have a solution of Zn(OH)_(2) that has a hydroxide ion concentration equal to 4.6times 10^-6M what is the solution? unsaturated supersaturated No answer text provided. saturated

Zn(OH)_(2) has a K_(sp) of 4.5times 10^-17 If you have a solution of Zn(OH)_(2) that has a hydroxide ion concentration equal to 4.6times 10^-6M what is the solution? unsaturated supersaturated No answer text provided. saturated
Zn(OH)_(2) has a K_(sp) of 4.5times 10^-17 If you have a solution of Zn(OH)_(2) that has a hydroxide ion
concentration equal to 4.6times 10^-6M what is the solution?
unsaturated
supersaturated
No answer text provided.
saturated

Solution
4.5(92 votes)

Answer

unsaturated Explanation 1. Write the Dissolution Equation Zn(OH)_2(s) \rightleftharpoons Zn^{2+}(aq) + 2OH^-(aq) 2. Express K_{sp} in Terms of Ion Concentrations K_{sp} = [Zn^{2+}][OH^-]^2 3. Calculate [Zn^{2+}] Using Given [OH^-] [Zn^{2+}] = \frac{K_{sp}} OH^-]^2} = \frac{4.5 \times 10^{-17}}{(4.6 \times 10^{-6})^2} 4. Perform the Calculation [Zn^{2+}] = \frac{4.5 \times 10^{-17}}{2.116 \times 10^{-11}} \approx 2.13 \times 10^{-6} M 5. Determine Saturation Level Compare calculated [Zn^{2+}] with actual concentration. If actual [Zn^{2+}] is less than 2.13 \times 10^{-6} M, the solution is unsaturated.

Explanation

1. Write the Dissolution Equation<br /> $Zn(OH)_2(s) \rightleftharpoons Zn^{2+}(aq) + 2OH^-(aq)$<br /><br />2. Express $K_{sp}$ in Terms of Ion Concentrations<br /> $K_{sp} = [Zn^{2+}][OH^-]^2$<br /><br />3. Calculate $[Zn^{2+}]$ Using Given $[OH^-]$<br /> $[Zn^{2+}] = \frac{K_{sp}}{[OH^-]^2} = \frac{4.5 \times 10^{-17}}{(4.6 \times 10^{-6})^2}$<br /><br />4. Perform the Calculation<br /> $[Zn^{2+}] = \frac{4.5 \times 10^{-17}}{2.116 \times 10^{-11}} \approx 2.13 \times 10^{-6} M$<br /><br />5. Determine Saturation Level<br /> Compare calculated $[Zn^{2+}]$ with actual concentration. If actual $[Zn^{2+}]$ is less than $2.13 \times 10^{-6} M$, the solution is unsaturated.
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