QuestionAugust 24, 2025

What is the value of f(-3) when f(x)=x^3-7x^2-4x-3 7 f(-3)= square

What is the value of f(-3) when f(x)=x^3-7x^2-4x-3 7 f(-3)= square
What is the value of f(-3) when f(x)=x^3-7x^2-4x-3 7
f(-3)= square

Solution
4.2(325 votes)

Answer

-81 Explanation 1. Substitute x = -3 into the function Replace x in f(x) = x^3 - 7x^2 - 4x - 3 with -3. 2. Calculate each term (-3)^3 = -27, -7(-3)^2 = -63, -4(-3) = 12, and constant -3 remains. 3. Sum the terms Add the results: -27 - 63 + 12 - 3.

Explanation

1. Substitute $x = -3$ into the function<br /> Replace $x$ in $f(x) = x^3 - 7x^2 - 4x - 3$ with $-3$.<br />2. Calculate each term<br /> $(-3)^3 = -27$, $-7(-3)^2 = -63$, $-4(-3) = 12$, and constant $-3$ remains.<br />3. Sum the terms<br /> Add the results: $-27 - 63 + 12 - 3$.
Click to rate: