QuestionAugust 26, 2025

Which of these standard form equations is equivalent to (x+1)(x-2)(x+4)(3x+7) x^4+10x^315x^2-50x-56 x^4+10x^3+15x^2-50x+56 3x^4+16x^3+3x^2-66x-56 3x^4+16x^3+3x^2-66x+56

Which of these standard form equations is equivalent to (x+1)(x-2)(x+4)(3x+7) x^4+10x^315x^2-50x-56 x^4+10x^3+15x^2-50x+56 3x^4+16x^3+3x^2-66x-56 3x^4+16x^3+3x^2-66x+56
Which of these standard form equations is equivalent to
(x+1)(x-2)(x+4)(3x+7)
x^4+10x^315x^2-50x-56
x^4+10x^3+15x^2-50x+56
3x^4+16x^3+3x^2-66x-56
3x^4+16x^3+3x^2-66x+56

Solution
4.6(271 votes)

Answer

3x^4 + 16x^3 + 3x^2 - 66x - 56 Explanation 1. Expand the expression Expand (x+1)(x-2)(x+4)(3x+7) using distribution. First, expand (x+1)(x-2) = x^2 - x - 2 and (x+4)(3x+7) = 3x^2 + 19x + 28. Then multiply these results: (x^2 - x - 2)(3x^2 + 19x + 28). 2. Multiply polynomials Use distribution to multiply: x^2(3x^2 + 19x + 28) = 3x^4 + 19x^3 + 28x^2 -x(3x^2 + 19x + 28) = -3x^3 - 19x^2 - 28x -2(3x^2 + 19x + 28) = -6x^2 - 38x - 56 3. Combine like terms Add all terms together: 3x^4 + (19x^3 - 3x^3) + (28x^2 - 19x^2 - 6x^2) + (-28x - 38x) - 56 Simplify: 3x^4 + 16x^3 + 3x^2 - 66x - 56

Explanation

1. Expand the expression<br /> Expand $(x+1)(x-2)(x+4)(3x+7)$ using distribution.<br /> First, expand $(x+1)(x-2) = x^2 - x - 2$ and $(x+4)(3x+7) = 3x^2 + 19x + 28$.<br /> Then multiply these results: $(x^2 - x - 2)(3x^2 + 19x + 28)$.<br /><br />2. Multiply polynomials<br /> Use distribution to multiply: <br /> $x^2(3x^2 + 19x + 28) = 3x^4 + 19x^3 + 28x^2$<br /> $-x(3x^2 + 19x + 28) = -3x^3 - 19x^2 - 28x$<br /> $-2(3x^2 + 19x + 28) = -6x^2 - 38x - 56$<br /><br />3. Combine like terms<br /> Add all terms together: <br /> $3x^4 + (19x^3 - 3x^3) + (28x^2 - 19x^2 - 6x^2) + (-28x - 38x) - 56$<br /> Simplify: $3x^4 + 16x^3 + 3x^2 - 66x - 56$
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