QuestionAugust 25, 2025

x^-2 y((y^4)/(x^2)-(x^4)/(y^2))

x^-2 y((y^4)/(x^2)-(x^4)/(y^2))
x^-2 y((y^4)/(x^2)-(x^4)/(y^2))

Solution
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Answer

\frac{y^7 - x^6 y}{x^4 y^2} Explanation 1. Simplify the expression inside the parentheses Calculate \frac{y^4}{x^2} - \frac{x^4}{y^2}. This becomes \frac{y^6 - x^6}{x^2 y^2}. 2. Multiply by x^{-2} y Distribute x^{-2} y to \frac{y^6 - x^6}{x^2 y^2}. This results in \frac{y^7 - x^6 y}{x^4 y^2}.

Explanation

1. Simplify the expression inside the parentheses<br /> Calculate $\frac{y^4}{x^2} - \frac{x^4}{y^2}$.<br /> This becomes $\frac{y^6 - x^6}{x^2 y^2}$.<br /><br />2. Multiply by $x^{-2} y$<br /> Distribute $x^{-2} y$ to $\frac{y^6 - x^6}{x^2 y^2}$.<br /> This results in $\frac{y^7 - x^6 y}{x^4 y^2}$.
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