QuestionJuly 11, 2025

When this equation is balanced, the coefficient in front of AlCl_(3) is __ underline ( )KCl+underline ( )Al_(2)(SO_(4))_(3)arrow underline ( )K_(2)SO_(4)+underline ( )AlCl_(3) 3 1 2 6

When this equation is balanced, the coefficient in front of AlCl_(3) is __ underline ( )KCl+underline ( )Al_(2)(SO_(4))_(3)arrow underline ( )K_(2)SO_(4)+underline ( )AlCl_(3) 3 1 2 6
When this equation is balanced, the coefficient in front of
AlCl_(3) is __
underline ( )KCl+underline ( )Al_(2)(SO_(4))_(3)arrow underline ( )K_(2)SO_(4)+underline ( )AlCl_(3)
3
1
2
6

Solution
4.3(153 votes)

Answer

2 Explanation 1. Identify the number of atoms Count atoms for each element on both sides. - Left: K=1, Al=2, Cl=0, S=3, O=12 - Right: K=2, Al=1, Cl=3, S=1, O=4 2. Balance Potassium (K) Multiply KCl by 2 to balance K. - New Left: K=2, Al=2, Cl=0, S=3, O=12 3. Balance Sulfur (S) and Oxygen (O) Multiply K_2SO_4 by 3 to balance S and O. - New Right: K=6, Al=1, Cl=3, S=3, O=12 4. Balance Aluminum (Al) Multiply AlCl_3 by 2 to balance Al. - New Right: K=6, Al=2, Cl=6, S=3, O=12 5. Balance Chlorine (Cl) Multiply KCl by 6 to balance Cl. - Final Left: K=6, Al=2, Cl=6, S=3, O=12

Explanation

1. Identify the number of atoms<br /> Count atoms for each element on both sides.<br />- Left: $K=1$, $Al=2$, $Cl=0$, $S=3$, $O=12$<br />- Right: $K=2$, $Al=1$, $Cl=3$, $S=1$, $O=4$<br /><br />2. Balance Potassium (K)<br /> Multiply $KCl$ by 2 to balance K.<br />- New Left: $K=2$, $Al=2$, $Cl=0$, $S=3$, $O=12$<br /><br />3. Balance Sulfur (S) and Oxygen (O)<br /> Multiply $K_2SO_4$ by 3 to balance S and O.<br />- New Right: $K=6$, $Al=1$, $Cl=3$, $S=3$, $O=12$<br /><br />4. Balance Aluminum (Al)<br /> Multiply $AlCl_3$ by 2 to balance Al.<br />- New Right: $K=6$, $Al=2$, $Cl=6$, $S=3$, $O=12$<br /><br />5. Balance Chlorine (Cl)<br /> Multiply $KCl$ by 6 to balance Cl.<br />- Final Left: $K=6$, $Al=2$, $Cl=6$, $S=3$, $O=12$
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