QuestionJuly 12, 2025

Use the balanced equation, 4Al+3O_(2)arrow 2Al_(2)O_(3) to answer the following question. How many grams of O_(2) are needed to react completely with 14.3 g of Al? Be sure your answer has the correct number of significant figures. square g O_(2)

Use the balanced equation, 4Al+3O_(2)arrow 2Al_(2)O_(3) to answer the following question. How many grams of O_(2) are needed to react completely with 14.3 g of Al? Be sure your answer has the correct number of significant figures. square g O_(2)
Use the balanced equation, 4Al+3O_(2)arrow 2Al_(2)O_(3) to answer the following question.
How many grams of O_(2) are needed to react completely with 14.3 g of Al? Be sure your answer has the correct number of significant figures.
square  g O_(2)

Solution
4.2(271 votes)

Answer

15.8 g O_{2} Explanation 1. Calculate moles of Al Use the molar mass of Al, which is 26.98 g/mol. Moles of Al = \frac{14.3 \text{ g}}{26.98 \text{ g/mol}}. 2. Determine moles of O_2 needed From the balanced equation, 4 moles of Al react with 3 moles of O_2. Use the ratio \frac{3}{4} to find moles of O_2: Moles of O_2 = Moles of Al \times \frac{3}{4}. 3. Convert moles of O_2 to grams Use the molar mass of O_2, which is 32.00 g/mol. Grams of O_2 = Moles of O_2 \times 32.00 \text{ g/mol}.

Explanation

1. Calculate moles of Al<br /> Use the molar mass of Al, which is 26.98 g/mol. Moles of Al = $\frac{14.3 \text{ g}}{26.98 \text{ g/mol}}$.<br /><br />2. Determine moles of $O_2$ needed<br /> From the balanced equation, 4 moles of Al react with 3 moles of $O_2$. Use the ratio $\frac{3}{4}$ to find moles of $O_2$: Moles of $O_2$ = Moles of Al $\times \frac{3}{4}$.<br /><br />3. Convert moles of $O_2$ to grams<br /> Use the molar mass of $O_2$, which is 32.00 g/mol. Grams of $O_2$ = Moles of $O_2 \times 32.00 \text{ g/mol}$.
Click to rate:

Similar Questions