QuestionDecember 19, 2025

The decomposition of NH_(4)HS is an endothermic reaction 1NH_(4)HS(s)leftharpoons 1NH_(3)(g)+1H_(2)S(g) Which change to this reaction will increase the concentration H_(2)S , Adecrease in the volume at a constant temperature (decrease in the concentration of NH_(4)HS An increase in temperature none of the above

The decomposition of NH_(4)HS is an endothermic reaction 1NH_(4)HS(s)leftharpoons 1NH_(3)(g)+1H_(2)S(g) Which change to this reaction will increase the concentration H_(2)S , Adecrease in the volume at a constant temperature (decrease in the concentration of NH_(4)HS An increase in temperature none of the above
The decomposition of NH_(4)HS is an endothermic reaction 1NH_(4)HS(s)leftharpoons 1NH_(3)(g)+1H_(2)S(g) Which change to this reaction will increase the concentration H_(2)S , Adecrease in the volume at a constant temperature (decrease in the concentration of NH_(4)HS An increase in temperature none of the above

Solution
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Answer

An increase in temperature Explanation 1. Analyze effect of volume decrease Decreasing volume increases pressure, favoring fewer moles of gas. The reaction produces 2 moles of gas from 0, so decreasing volume shifts equilibrium left, decreasing H_2S. 2. Analyze effect of decreasing NH_4HS concentration NH_4HS is a solid; its concentration does not affect equilibrium position for gases. 3. Analyze effect of temperature increase The reaction is endothermic. Increasing temperature favors the forward (endothermic) direction, increasing H_2S concentration. 4. Consider "none of the above" Previous analysis shows that increasing temperature will increase H_2S.

Explanation

1. Analyze effect of volume decrease<br /> Decreasing volume increases pressure, favoring fewer moles of gas. The reaction produces 2 moles of gas from 0, so decreasing volume shifts equilibrium left, decreasing $H_2S$.<br />2. Analyze effect of decreasing $NH_4HS$ concentration<br /> $NH_4HS$ is a solid; its concentration does not affect equilibrium position for gases.<br />3. Analyze effect of temperature increase<br /> The reaction is endothermic. Increasing temperature favors the forward (endothermic) direction, increasing $H_2S$ concentration.<br />4. Consider "none of the above"<br /> Previous analysis shows that increasing temperature will increase $H_2S$.
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