QuestionDecember 19, 2025

39. Optional extra credit: Cakulate the number of Nitrogen atoms in the copper nitrate compound produced when 3 moles of copper (s) reacts with excess nitric acid

39. Optional extra credit: Cakulate the number of Nitrogen atoms in the copper nitrate compound produced when 3 moles of copper (s) reacts with excess nitric acid
39. Optional extra credit: Cakulate the number of Nitrogen atoms in the copper nitrate compound produced when 3 moles of copper (s) reacts with excess nitric acid

Solution
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Answer

3.61 \times 10^{24} nitrogen atoms Explanation 1. Write the balanced chemical equation 3\,Cu(s) + 8\,HNO_3(aq) \rightarrow 3\,Cu(NO_3)_2(aq) + 2\,NO(g) + 4\,H_2O(l) 2. Determine moles of copper nitrate produced 3 moles of Cu produce 3 moles of Cu(NO_3)_2. 3. Calculate moles of nitrogen atoms per mole of copper nitrate Each Cu(NO_3)_2 has 2 nitrate ions, each with 1 N atom; so 2 N atoms per formula unit. 4. Find total moles of nitrogen atoms 3 moles Cu(NO_3)_2 \times 2 moles N = 6 moles N atoms. 5. Convert moles of nitrogen atoms to number of atoms Use N = n \times N_A, where N_A = 6.022 \times 10^{23}. 6 \text{ moles} \times 6.022 \times 10^{23} = 3.6132 \times 10^{24} atoms.

Explanation

1. Write the balanced chemical equation<br /> $3\,Cu(s) + 8\,HNO_3(aq) \rightarrow 3\,Cu(NO_3)_2(aq) + 2\,NO(g) + 4\,H_2O(l)$<br /><br />2. Determine moles of copper nitrate produced<br /> 3 moles of Cu produce 3 moles of $Cu(NO_3)_2$.<br /><br />3. Calculate moles of nitrogen atoms per mole of copper nitrate<br /> Each $Cu(NO_3)_2$ has 2 nitrate ions, each with 1 N atom; so 2 N atoms per formula unit.<br /><br />4. Find total moles of nitrogen atoms<br /> $3$ moles $Cu(NO_3)_2 \times 2$ moles N = $6$ moles N atoms.<br /><br />5. Convert moles of nitrogen atoms to number of atoms<br /> Use $N = n \times N_A$, where $N_A = 6.022 \times 10^{23}$.<br /> $6 \text{ moles} \times 6.022 \times 10^{23} = 3.6132 \times 10^{24}$ atoms.
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