QuestionAugust 26, 2025

Find the value of a and YZ If Yis between Xand Z. XY=3a-4,YZ=6a+2,XZ=5a+22 a=square ; YZ=square

Find the value of a and YZ If Yis between Xand Z. XY=3a-4,YZ=6a+2,XZ=5a+22 a=square ; YZ=square
Find the value of a and YZ If Yis between Xand Z.
XY=3a-4,YZ=6a+2,XZ=5a+22
a=square ;
YZ=square

Solution
4.4(212 votes)

Answer

a = 6; \quad YZ = 38 Explanation 1. Set up the equation Since Y is between X and Z, we have XY + YZ = XZ. Therefore, (3a - 4) + (6a + 2) = 5a + 22. 2. Simplify the equation Combine like terms: 9a - 2 = 5a + 22. 3. Solve for a Subtract 5a from both sides: 4a - 2 = 22. Add 2 to both sides: 4a = 24. Divide by 4: a = 6. 4. Calculate YZ Substitute a = 6 into YZ = 6a + 2: YZ = 6(6) + 2 = 36 + 2 = 38.

Explanation

1. Set up the equation<br /> Since $Y$ is between $X$ and $Z$, we have $XY + YZ = XZ$. Therefore, $(3a - 4) + (6a + 2) = 5a + 22$.<br />2. Simplify the equation<br /> Combine like terms: $9a - 2 = 5a + 22$.<br />3. Solve for $a$<br /> Subtract $5a$ from both sides: $4a - 2 = 22$. Add 2 to both sides: $4a = 24$. Divide by 4: $a = 6$.<br />4. Calculate $YZ$<br /> Substitute $a = 6$ into $YZ = 6a + 2$: $YZ = 6(6) + 2 = 36 + 2 = 38$.
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