QuestionMay 29, 2026

Which equation represents a line that has a slope of -(1)/(2) and passes through point (4,-5) y=-(1)/(2)x+(3)/(2) y=-(1)/(2)x+(13)/(2) y=-(1)/(2)x-7 y=-(1)/(2)x-3

Which equation represents a line that has a slope of -(1)/(2) and passes through point (4,-5) y=-(1)/(2)x+(3)/(2) y=-(1)/(2)x+(13)/(2) y=-(1)/(2)x-7 y=-(1)/(2)x-3
Which equation represents a line that has a slope of -(1)/(2)
and passes through point (4,-5)
y=-(1)/(2)x+(3)/(2)
y=-(1)/(2)x+(13)/(2)
y=-(1)/(2)x-7
y=-(1)/(2)x-3

Solution
4.2(248 votes)

Answer

y = -\frac{1}{2}x - 3 Explanation 1. Apply the point-slope formula Use the point-slope form y - y_1 = m(x - x_1) with m = -\frac{1}{2} and (x_1, y_1) = (4, -5). y - (-5) = -\frac{1}{2}(x - 4) 2. Simplify to slope-intercept form Distribute the slope and isolate y to match the form y = mx + b. y + 5 = -\frac{1}{2}x + 2 y = -\frac{1}{2}x + 2 - 5 y = -\frac{1}{2}x - 3

Explanation

1. Apply the point-slope formula<br />Use the point-slope form $y - y_1 = m(x - x_1)$ with $m = -\frac{1}{2}$ and $(x_1, y_1) = (4, -5)$.<br />$y - (-5) = -\frac{1}{2}(x - 4)$<br /><br />2. Simplify to slope-intercept form<br />Distribute the slope and isolate $y$ to match the form $y = mx + b$.<br />$y + 5 = -\frac{1}{2}x + 2$<br />$y = -\frac{1}{2}x + 2 - 5$<br />$y = -\frac{1}{2}x - 3$
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