QuestionDecember 15, 2025

For a given process a system emits 322kJ of heat at the same as it performs 22 kJ of work The values of Delta H and Delta E respectively are 322kJ and 344kJ -322kJ and -344kJ -344kJ and -322kJ 344kJ and 322kJ

For a given process a system emits 322kJ of heat at the same as it performs 22 kJ of work The values of Delta H and Delta E respectively are 322kJ and 344kJ -322kJ and -344kJ -344kJ and -322kJ 344kJ and 322kJ
For a given process a system emits 322kJ of heat at
the same as it performs 22 kJ of work
The values of Delta H and Delta E respectively are
322kJ and 344kJ
-322kJ and -344kJ
-344kJ and -322kJ
344kJ and 322kJ

Solution
4.4(287 votes)

Answer

-322 kJ and -344 kJ Explanation 1. Assign signs to heat and work System emits heat: q = -322 kJ. System does work: w = -22 kJ. 2. Calculate \Delta E using the first law \Delta E = q + w = -322 + (-22) = -344 kJ. 3. Calculate \Delta H for constant pressure \Delta H = q_p. Here, q_p = q = -322 kJ.

Explanation

1. Assign signs to heat and work<br /> System emits heat: $q = -322$ kJ. System does work: $w = -22$ kJ.<br />2. Calculate $\Delta E$ using the first law<br /> $\Delta E = q + w = -322 + (-22) = -344$ kJ.<br />3. Calculate $\Delta H$ for constant pressure<br /> $\Delta H = q_p$. Here, $q_p = q = -322$ kJ.
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