QuestionDecember 15, 2025

When a stone is dropped in a pond ripples are formed and travel in concentric circles away from where the stone. was dropped. The equation of the least-squares regression line is hat (Area)=0.010+3.141(Time^2) What is the predicted area, in cm^2 of the circle 8 seconds after the stone was dropped? 25.14cm^2 50.27cm^2 64.01cm^2 201.03cm^2

When a stone is dropped in a pond ripples are formed and travel in concentric circles away from where the stone. was dropped. The equation of the least-squares regression line is hat (Area)=0.010+3.141(Time^2) What is the predicted area, in cm^2 of the circle 8 seconds after the stone was dropped? 25.14cm^2 50.27cm^2 64.01cm^2 201.03cm^2
When a stone is dropped in a pond ripples are formed and travel in concentric circles away from where the stone.
was dropped. The equation of the least-squares regression line is
hat (Area)=0.010+3.141(Time^2) What is the
predicted area, in cm^2 of the circle 8 seconds after the stone was dropped?
25.14cm^2
50.27cm^2
64.01cm^2
201.03cm^2

Solution
4.4(176 votes)

Answer

201.03\ \text{cm}^2 Explanation 1. Substitute Time into Regression Equation Plug Time = 8 into \hat{Area} = 0.010 + 3.141(Time^2). 2. Calculate Time^2 8^2 = 64 3. Compute Predicted Area \hat{Area} = 0.010 + 3.141 \times 64 = 0.010 + 201.024 = 201.034

Explanation

1. Substitute Time into Regression Equation<br /> Plug $Time = 8$ into $\hat{Area} = 0.010 + 3.141(Time^2)$.<br /><br />2. Calculate $Time^2$<br /> $8^2 = 64$<br /><br />3. Compute Predicted Area<br /> $\hat{Area} = 0.010 + 3.141 \times 64 = 0.010 + 201.024 = 201.034$
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