QuestionAugust 27, 2025

(5^2-3^4)/((2^3)-5)cdot (6^(2div 9))

(5^2-3^4)/((2^3)-5)cdot (6^(2div 9))
(5^2-3^4)/((2^3)-5)cdot (6^(2div 9))

Solution
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Answer

-\frac{14}{3} Explanation 1. Calculate powers 5^2 = 25 and 3^4 = 81 2. Subtract powers 25 - 81 = -56 3. Calculate other operations 2^3 = 8, so 8 - 5 = 3 6^2 = 36, and 36 \div 9 = 4 4. Multiply results 3 \cdot 4 = 12 5. Divide final results \frac{-56}{12} = -\frac{14}{3}

Explanation

1. Calculate powers<br /> $5^2 = 25$ and $3^4 = 81$<br />2. Subtract powers<br /> $25 - 81 = -56$<br />3. Calculate other operations<br /> $2^3 = 8$, so $8 - 5 = 3$<br /> $6^2 = 36$, and $36 \div 9 = 4$<br />4. Multiply results<br /> $3 \cdot 4 = 12$<br />5. Divide final results<br /> $\frac{-56}{12} = -\frac{14}{3}$
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