QuestionJuly 7, 2025

Determine the amount of heat (in kJ) associated with the production of 1.32times 10^4g of NO_(2) according to the following equation: 2NO(g)+O_(2)(g)arrow 2NO_(2)(g) Delta H=-114.6(kJ)/(mol) Be sure your answer has the correct number of significant digits. square kJ

Determine the amount of heat (in kJ) associated with the production of 1.32times 10^4g of NO_(2) according to the following equation: 2NO(g)+O_(2)(g)arrow 2NO_(2)(g) Delta H=-114.6(kJ)/(mol) Be sure your answer has the correct number of significant digits. square kJ
Determine the amount of heat (in kJ) associated with the production of 1.32times 10^4g of NO_(2) according to the following equation:
2NO(g)+O_(2)(g)arrow 2NO_(2)(g) Delta H=-114.6(kJ)/(mol)
Be sure your answer has the correct number of significant digits.
square  kJ

Solution
4.3(257 votes)

Answer

-3.29 \times 10^4 \, \text{kJ} Explanation 1. Calculate moles of NO_2 Molar mass of NO_2 is 14.01 + 2 \times 16.00 = 46.01 \, g/mol. Moles of NO_2 = \frac{1.32 \times 10^4 \, g}{46.01 \, g/mol}. 2. Calculate heat associated with the reaction Use \Delta H = -114.6 \, \text{kJ/mol}. Total heat = moles of NO_2 \times \Delta H.

Explanation

1. Calculate moles of $NO_2$<br /> Molar mass of $NO_2$ is $14.01 + 2 \times 16.00 = 46.01 \, g/mol$. Moles of $NO_2 = \frac{1.32 \times 10^4 \, g}{46.01 \, g/mol}$.<br /><br />2. Calculate heat associated with the reaction<br /> Use $\Delta H = -114.6 \, \text{kJ/mol}$. Total heat = moles of $NO_2 \times \Delta H$.
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