QuestionJuly 27, 2025

(b) (15 points) If 32.05 ml of the NaOH standard are found to neutralize 25.00 ml of an unknown acid solution, determine the molarity of the unknown.

(b) (15 points) If 32.05 ml of the NaOH standard are found to neutralize 25.00 ml of an unknown acid solution, determine the molarity of the unknown.
(b) (15 points) If 32.05 ml of the NaOH standard are found to neutralize 25.00 ml of an
unknown acid solution, determine the molarity of the unknown.

Solution
3.6(237 votes)

Answer

M_{acid} = \frac{32.05}{25.00} \times M_{NaOH} Explanation 1. Calculate moles of NaOH Assume the molarity of NaOH is M_{NaOH}. Moles of NaOH = 32.05 \, \text{ml} \times M_{NaOH}. 2. Use neutralization equation Neutralization implies moles of NaOH = moles of acid. Therefore, 32.05 \, \text{ml} \times M_{NaOH} = 25.00 \, \text{ml} \times M_{acid}. 3. Solve for molarity of the unknown acid Rearrange to find M_{acid}: M_{acid} = \frac{32.05 \, \text{ml} \times M_{NaOH}}{25.00 \, \text{ml}}.

Explanation

1. Calculate moles of NaOH<br /> Assume the molarity of NaOH is $M_{NaOH}$. Moles of NaOH = $32.05 \, \text{ml} \times M_{NaOH}$.<br />2. Use neutralization equation<br /> Neutralization implies moles of NaOH = moles of acid. Therefore, $32.05 \, \text{ml} \times M_{NaOH} = 25.00 \, \text{ml} \times M_{acid}$.<br />3. Solve for molarity of the unknown acid<br /> Rearrange to find $M_{acid}$: $M_{acid} = \frac{32.05 \, \text{ml} \times M_{NaOH}}{25.00 \, \text{ml}}$.
Click to rate:

Similar Questions