QuestionMay 19, 2026

Solve the equation given by completing the square. 5x^2+20x-25=0 [Hint: Divide by 5 first] x=square

Solve the equation given by completing the square. 5x^2+20x-25=0 [Hint: Divide by 5 first] x=square
Solve the equation given by completing the square.
5x^2+20x-25=0
[Hint: Divide by 5 first]
x=square

Solution
4.4(234 votes)

Answer

x = 1, \ -5 Explanation 1. Simplify by dividing through by 5 5x^2 + 20x - 25 = 0 \ \Rightarrow \ x^2 + 4x - 5 = 0 2. Isolate constant term x^2 + 4x = 5 3. Complete the square Add (\frac{4}{2})^2 = 4 to both sides: x^2 + 4x + 4 = 5 + 4 4. Rewrite perfect square and solve (x+2)^2 = 9 x+2 = \pm 3 5. Find x values x = 1 or x = -5

Explanation

1. Simplify by dividing through by 5 <br /> $5x^2 + 20x - 25 = 0 \ \Rightarrow \ x^2 + 4x - 5 = 0$ <br /><br />2. Isolate constant term <br /> $x^2 + 4x = 5$ <br /><br />3. Complete the square <br /> Add $(\frac{4}{2})^2 = 4$ to both sides: <br /> $x^2 + 4x + 4 = 5 + 4$ <br /><br />4. Rewrite perfect square and solve <br /> $(x+2)^2 = 9$ <br /> $x+2 = \pm 3$ <br /><br />5. Find $x$ values <br /> $x = 1$ or $x = -5$
Click to rate:

Similar Questions