QuestionMay 24, 2025

How many grams of sodium azide (NaN_(3)) is required to inflate an airbag to 67L of N_(2) at STP? express with 3 sig figs __

How many grams of sodium azide (NaN_(3)) is required to inflate an airbag to 67L of N_(2) at STP? express with 3 sig figs __
How many grams of sodium azide (NaN_(3)) is required to inflate an airbag to 67L of N_(2) at STP? express with 3 sig figs __

Solution
3.3(266 votes)

Answer

130 g Explanation 1. Determine moles of N_2 at STP At STP, 1 mole of gas occupies 22.4 L. Moles of N_2 = \frac{67 \text{ L}}{22.4 \text{ L/mol}}. 2. Calculate moles of NaN_3 needed The balanced reaction is 2NaN_3 \rightarrow 2Na + 3N_2. From the stoichiometry, \frac{2}{3} moles of NaN_3 produce 1 mole of N_2. Multiply moles of N_2 by \frac{2}{3} to find moles of NaN_3. 3. Convert moles of NaN_3 to grams Use molar mass of NaN_3 (65.01 g/mol). Grams of NaN_3 = \text{moles of } NaN_3 \times 65.01 \text{ g/mol}.

Explanation

1. Determine moles of $N_2$ at STP<br /> At STP, 1 mole of gas occupies 22.4 L. Moles of $N_2 = \frac{67 \text{ L}}{22.4 \text{ L/mol}}$.<br /><br />2. Calculate moles of $NaN_3$ needed<br /> The balanced reaction is $2NaN_3 \rightarrow 2Na + 3N_2$. From the stoichiometry, $\frac{2}{3}$ moles of $NaN_3$ produce 1 mole of $N_2$. Multiply moles of $N_2$ by $\frac{2}{3}$ to find moles of $NaN_3$.<br /><br />3. Convert moles of $NaN_3$ to grams<br /> Use molar mass of $NaN_3$ (65.01 g/mol). Grams of $NaN_3 = \text{moles of } NaN_3 \times 65.01 \text{ g/mol}$.
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