QuestionMarch 20, 2026

You're driving down a highway late one night at 20m/s when a deer steps onto the road 35 m in front of you. Your reaction time before stepping on the breaks is 0.50 s, and the maximum deceleration of your car is 10m/s^2 How much distance is between you and the deer when you come to a stop? 10 m Om 5.0 m 35 m 30 m

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Answer

5.0 m Explanation 1. Calculate distance traveled during reaction time d_{\text{reaction}} = v \times t_{\text{reaction}} = 20 \times 0.50 = 10\ \text{m} 2. Calculate braking distance Use **d = \frac{v^{2}}{2a}**, with v=20\ \text{m/s} and a=10\ \text{m/s}^2: d_{\text{brake}} = \frac{20^{2}}{2 \times 10} = \frac{400}{20} = 20\ \text{m} 3. Total stopping distance d_{\text{total}} = d_{\text{reaction}} + d_{\text{brake}} = 10 + 20 = 30\ \text{m} 4. Distance left between car and deer d_{\text{left}} = 35 - 30 = 5\ \text{m}

Explanation

1. Calculate distance traveled during reaction time $d_{\text{reaction}} = v \times t_{\text{reaction}} = 20 \times 0.50 = 10\ \text{m}$ 2. Calculate braking distance Use **$d = \frac{v^{2}}{2a}$**, with $v=20\ \text{m/s}$ and $a=10\ \text{m/s}^2$: $d_{\text{brake}} = \frac{20^{2}}{2 \times 10} = \frac{400}{20} = 20\ \text{m}$ 3. Total stopping distance $d_{\text{total}} = d_{\text{reaction}} + d_{\text{brake}} = 10 + 20 = 30\ \text{m}$ 4. Distance left between car and deer $d_{\text{left}} = 35 - 30 = 5\ \text{m}$

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