QuestionMay 27, 2025

A piece of sodium metal reacts completely with water according to the reaction: 2Na(s)+2H_(2)O(l)arrow 2NaOH(aq)+H_(2)(g) The hydrogen gas is collected over water at 25^circ C . The volume of the gas generated is 246 mL at 760.0 mmHg. Calculate the number of grams of sodium consumed in the reaction. __ g Na

A piece of sodium metal reacts completely with water according to the reaction: 2Na(s)+2H_(2)O(l)arrow 2NaOH(aq)+H_(2)(g) The hydrogen gas is collected over water at 25^circ C . The volume of the gas generated is 246 mL at 760.0 mmHg. Calculate the number of grams of sodium consumed in the reaction. __ g Na
A piece of sodium metal reacts completely with water
according to the reaction:
2Na(s)+2H_(2)O(l)arrow 2NaOH(aq)+H_(2)(g)
The hydrogen gas is collected over water at 25^circ C . The
volume of the gas generated is 246 mL at 760.0 mmHg.
Calculate the number of grams of sodium consumed in the
reaction. __ g Na

Solution
4.0(202 votes)

Answer

0.464 g Na Explanation 1. Calculate moles of H_2 gas Use the ideal gas law: **PV = nRT**. Convert 246 mL to liters (0.246 L) and 760 mmHg to atm (1 atm). At 25^{\circ}C, R = 0.0821 \, \text{L atm/mol K} and T = 298 \, \text{K}. n = \frac{PV}{RT} = \frac{(1)(0.246)}{0.0821 \times 298} \approx 0.0101 \, \text{mol} 2. Determine moles of Na From the balanced equation, 1 mole of H_2 is produced from 2 moles of Na. Therefore, moles of Na = 2 \times 0.0101 = 0.0202 \, \text{mol}. 3. Calculate grams of Na Use the molar mass of Na (22.99 g/mol): Mass = 0.0202 \times 22.99 \approx 0.464 \, \text{g}

Explanation

1. Calculate moles of $H_2$ gas<br /> Use the ideal gas law: **$PV = nRT$**. Convert 246 mL to liters (0.246 L) and 760 mmHg to atm (1 atm). At $25^{\circ}C$, $R = 0.0821 \, \text{L atm/mol K}$ and $T = 298 \, \text{K}$.<br /> $n = \frac{PV}{RT} = \frac{(1)(0.246)}{0.0821 \times 298} \approx 0.0101 \, \text{mol}$<br /><br />2. Determine moles of Na<br /> From the balanced equation, 1 mole of $H_2$ is produced from 2 moles of Na. Therefore, moles of Na = $2 \times 0.0101 = 0.0202 \, \text{mol}$.<br /><br />3. Calculate grams of Na<br /> Use the molar mass of Na (22.99 g/mol): Mass = $0.0202 \times 22.99 \approx 0.464 \, \text{g}$
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