QuestionMay 26, 2025

Calculate the volume of 86mu g of a gas whose density is 1.225times 10^-3g/mL Express your answer in milliliters using the correct number of significant figures. Do not enter your answer using scientific notation. Volume=square mL

Calculate the volume of 86mu g of a gas whose density is 1.225times 10^-3g/mL Express your answer in milliliters using the correct number of significant figures. Do not enter your answer using scientific notation. Volume=square mL
Calculate the volume of 86mu g of a gas whose density is 1.225times 10^-3g/mL Express your
answer in milliliters using the correct number of significant figures. Do not enter your answer
using scientific notation.
Volume=square mL

Solution
4.4(322 votes)

Answer

0.070 mL Explanation 1. Convert mass to grams Convert 86 micrograms (ug) to grams: 86 \, \text{ug} = 86 \times 10^{-6} \, \text{g} = 0.000086 \, \text{g}. 2. Use the density formula **Density formula**: \text{Density} = \frac{\text{Mass}}{\text{Volume}}. Rearrange to find volume: \text{Volume} = \frac{\text{Mass}}{\text{Density}}. 3. Calculate the volume Substitute the values: \text{Volume} = \frac{0.000086 \, \text{g}}{1.225 \times 10^{-3} \, \text{g/mL}} = 0.07020408163 \, \text{mL}. 4. Apply significant figures The mass has two significant figures, so round the volume to two significant figures: 0.070 \, \text{mL}.

Explanation

1. Convert mass to grams<br /> Convert 86 micrograms (ug) to grams: $86 \, \text{ug} = 86 \times 10^{-6} \, \text{g} = 0.000086 \, \text{g}$.<br /><br />2. Use the density formula<br /> **Density formula**: $ \text{Density} = \frac{\text{Mass}}{\text{Volume}}$. Rearrange to find volume: $ \text{Volume} = \frac{\text{Mass}}{\text{Density}}$.<br /><br />3. Calculate the volume<br /> Substitute the values: $ \text{Volume} = \frac{0.000086 \, \text{g}}{1.225 \times 10^{-3} \, \text{g/mL}} = 0.07020408163 \, \text{mL}$.<br /><br />4. Apply significant figures<br /> The mass has two significant figures, so round the volume to two significant figures: $0.070 \, \text{mL}$.
Click to rate:

Similar Questions