QuestionJune 12, 2025

Aluminum-27 combines with a neutron to produce a proton and a nuclide. Identify the balanced nuclear equation for this scenario. (}_{13)^27Al+_(0)^1narrow _(1)^1p+_(12)^25Mg (}_{13)^27Al+_(0)^1narrow _(1)^1p+_(14)^29Si (}_{13)^27Al+_(0)^1narrow _(1)^1p+_(12)^27Mg (}_{13)^27Al+_(1)^1parrow _(0)^1n+_(14)^27Si

Aluminum-27 combines with a neutron to produce a proton and a nuclide. Identify the balanced nuclear equation for this scenario. (}_{13)^27Al+_(0)^1narrow _(1)^1p+_(12)^25Mg (}_{13)^27Al+_(0)^1narrow _(1)^1p+_(14)^29Si (}_{13)^27Al+_(0)^1narrow _(1)^1p+_(12)^27Mg (}_{13)^27Al+_(1)^1parrow _(0)^1n+_(14)^27Si
Aluminum-27 combines with a neutron to produce a proton and a nuclide. Identify the balanced nuclear
equation for this scenario.
(}_{13)^27Al+_(0)^1narrow _(1)^1p+_(12)^25Mg
(}_{13)^27Al+_(0)^1narrow _(1)^1p+_(14)^29Si
(}_{13)^27Al+_(0)^1narrow _(1)^1p+_(12)^27Mg
(}_{13)^27Al+_(1)^1parrow _(0)^1n+_(14)^27Si

Solution
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Answer

{}_{13}^{27}Al+_{0}^{1}n\rightarrow _{1}^{1}p+_{12}^{27}Mg Explanation 1. Identify the initial and final particles Aluminum-27 ({}_{13}^{27}Al) combines with a neutron ({}_{0}^{1}n), producing a proton ({}_{1}^{1}p) and a nuclide. 2. Apply conservation of atomic number The atomic number before the reaction is 13 (Al) + 0 (n) = 13. After the reaction, it should be 1 (p) + X, where X is the atomic number of the unknown nuclide. Thus, X = 12. 3. Apply conservation of mass number The mass number before the reaction is 27 (Al) + 1 (n) = 28. After the reaction, it should be 1 (p) + Y, where Y is the mass number of the unknown nuclide. Thus, Y = 27. 4. Identify the nuclide The nuclide with atomic number 12 and mass number 27 is Magnesium-27 ({}_{12}^{27}Mg).

Explanation

1. Identify the initial and final particles<br /> Aluminum-27 (${}_{13}^{27}Al$) combines with a neutron (${}_{0}^{1}n$), producing a proton (${}_{1}^{1}p$) and a nuclide.<br /><br />2. Apply conservation of atomic number<br /> The atomic number before the reaction is 13 (Al) + 0 (n) = 13. After the reaction, it should be 1 (p) + X, where X is the atomic number of the unknown nuclide. Thus, X = 12.<br /><br />3. Apply conservation of mass number<br /> The mass number before the reaction is 27 (Al) + 1 (n) = 28. After the reaction, it should be 1 (p) + Y, where Y is the mass number of the unknown nuclide. Thus, Y = 27.<br /><br />4. Identify the nuclide<br /> The nuclide with atomic number 12 and mass number 27 is Magnesium-27 (${}_{12}^{27}Mg$).
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