A student used 715 g of CaCl_(2) and 9.25 g of K_(2)CO_(3) to make CaCO_(3) The actual yield was 6.15 g of CaCO_(3) Calculate the limiting reagent. CaCl_(2)+K_(2)CO_(3)^a2KCl+CaCO_(3) 9.25 g of K_(2)CO_(3) 7.15 g mol of CaCl_(2) 6.15g CaCO_(3)

2 mol of an ideal diatomic gas are cooled at constant volume until the pressure is reduced to $1/3$ the initial pressure . What is the entropy change of the gas? A. $-63.9J/K$ B $+63.9J/K$ C. $-9.13J/K$ D. 0 E. $-45.6J/k$

Carnotite $(K_{2}(UO_{2})_{2}(VO_{4})_{2})$ and is one of 3 common vanadium ores. Vanadium metal can be extracted from this ore as pure vanadium. If you start with 985 g of carnotite, what is the maximum number of grams of V that can be extracted? A. 59.2 grams B. 98.5 grams C. 118 grams D. 120 grams E. 130 grams

The number of moles present in 180 grams of hydrochloric acid is approximately __ 4.75 5.00 4.25 4.50

How many moles contain $5.75\times 10^{24}$ atoms of Al? $9.55\times 10^{2}$ $2.13\times 10^{23}$ mol 9.55 mol 2.13 mol

Which among the following statements is NOT TRUE regarding a mole? A mole is the SI unit to measure the amount of substance. $1mole=6.02\times 10^{23}representative\quad particles=Avogadro's\quad number$ The representative particle of most of the elements is a molecule. A "representative element"refers to the species present in the substance.

Which of the following representations is correct for a chemical equation? $Reactants=products$ $Reactants\rightarrow Products$ $Products\rightarrow Reactants$ $Reactants+products\rightarrow Products+reactants$

The number of moles of C in 3 moles of ethanol $(CH_{3}CH_{2}OH)$ is __ $6.02\times 10^{23}mol$ 6 mol 18 mol $4.5\times 10^{23}mol$

How many atoms does a mole of atoms contain? $6.022\times 10^{23}atoms$ $60.22\times 10^{23}atoms$ $6.202\times 10^{23}atoms$ $6.082\times 10^{23}atoms$

How many molecules are there in 75 grams of aluminum triflouride? $5.68\times 10^{23}$ $5.38\times 10^{23}$ $5.98\times 10^{23}$ $6.23\times 10^{23}$

How many moles of sodium atoms are there in 4.4 grams of sodium carbonate? A. \$2.5\times 10^{22}\$ moles \begin{array}{|c|c|c|} \hline 6\ &\ 8\ &\ 11\ \\ C\ &\ 0\ &\ Ns\ \\ 12.01\ &\ 16.00\ &\ 23.00\ \\ \hline \end{array} B. \$5.0\times 10^{22}\$ moles C. 0.04 moles D. 0.08 moles E. 0.12 moles