QuestionJune 18, 2025

How many moles of sodium atoms are there in 4.4 grams of sodium carbonate? A. 2.5times 10^22 moles 6 & 8 & 11 C & 0 & Ns 12.01 & 16.00 & 23.00 B. 5.0times 10^22 moles C. 0.04 moles D. 0.08 moles E. 0.12 moles

How many moles of sodium atoms are there in 4.4 grams of sodium carbonate? A. 2.5times 10^22 moles 6 & 8 & 11 C & 0 & Ns 12.01 & 16.00 & 23.00 B. 5.0times 10^22 moles C. 0.04 moles D. 0.08 moles E. 0.12 moles
How many moles of sodium atoms are there in 4.4 grams of
sodium carbonate?
A. 2.5times 10^22 moles


6 & 8 & 11 
C & 0 & Ns 
12.01 & 16.00 & 23.00 


B. 5.0times 10^22 moles
C. 0.04 moles
D. 0.08 moles
E. 0.12 moles

Solution
4.5(233 votes)

Answer

D. 0.08 moles Explanation 1. Calculate Molar Mass of Sodium Carbonate Sodium carbonate (Na_2CO_3) has a molar mass calculated as follows: 2 \times 23.00 + 12.01 + 3 \times 16.00 = 105.99 \, \text{g/mol}. 2. Calculate Moles of Sodium Carbonate Use the formula **moles = \frac{\text{mass}}{\text{molar mass}}**: \frac{4.4 \, \text{g}}{105.99 \, \text{g/mol}} \approx 0.0415 \, \text{moles}. 3. Calculate Moles of Sodium Atoms Each mole of Na_2CO_3 contains 2 moles of sodium atoms. Therefore, 0.0415 \times 2 = 0.083 \, \text{moles} of sodium atoms.

Explanation

1. Calculate Molar Mass of Sodium Carbonate<br /> Sodium carbonate ($Na_2CO_3$) has a molar mass calculated as follows: $2 \times 23.00 + 12.01 + 3 \times 16.00 = 105.99 \, \text{g/mol}$.<br /><br />2. Calculate Moles of Sodium Carbonate<br /> Use the formula **moles = \frac{\text{mass}}{\text{molar mass}}**: $\frac{4.4 \, \text{g}}{105.99 \, \text{g/mol}} \approx 0.0415 \, \text{moles}$.<br /><br />3. Calculate Moles of Sodium Atoms<br /> Each mole of $Na_2CO_3$ contains 2 moles of sodium atoms. Therefore, $0.0415 \times 2 = 0.083 \, \text{moles}$ of sodium atoms.
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