QuestionAugust 25, 2025

2. What is the solution to the system below? ) x+3y=0 2x-y=-7

2. What is the solution to the system below? ) x+3y=0 2x-y=-7
2. What is the solution to the system below? ) x+3y=0 2x-y=-7

Solution
3.6(244 votes)

Answer

x = -3, \; y = 1 Explanation 1. Express x in terms of y From the first equation, x + 3y = 0, solve for x: x = -3y. 2. Substitute x in the second equation Substitute x = -3y into 2x - y = -7: 2(-3y) - y = -7. 3. Simplify and solve for y Simplify to get -6y - y = -7, which is -7y = -7. Solve for y: y = 1. 4. Solve for x Substitute y = 1 back into x = -3y: x = -3(1) = -3.

Explanation

1. Express $x$ in terms of $y$<br /> From the first equation, $x + 3y = 0$, solve for $x$: $x = -3y$.<br />2. Substitute $x$ in the second equation<br /> Substitute $x = -3y$ into $2x - y = -7$: $2(-3y) - y = -7$.<br />3. Simplify and solve for $y$<br /> Simplify to get $-6y - y = -7$, which is $-7y = -7$. Solve for $y$: $y = 1$.<br />4. Solve for $x$<br /> Substitute $y = 1$ back into $x = -3y$: $x = -3(1) = -3$.
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