QuestionMarch 10, 2026

HCO_(3)+Mg(OH)_(2)arrow H_(2)O+MgCO_(3)

HCO_(3)+Mg(OH)_(2)arrow H_(2)O+MgCO_(3)
HCO_(3)+Mg(OH)_(2)arrow H_(2)O+MgCO_(3)

Solution
4.0(208 votes)

Answer

2\,HCO_3^- + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3 Explanation 1. Identify reaction type This is an acid-base reaction where bicarbonate reacts with magnesium hydroxide to form water and magnesium carbonate. 2. Balance magnesium and carbonate One Mg(OH)_2 reacts with two HCO_3^- because Mg(OH)_2 has two OH⁻ groups. 3. Balance hydrogen and oxygen Each HCO_3 provides one H to form water, matching OH⁻ from Mg(OH)_2. 4. Final balanced equation 2\,HCO_3^- + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3 + CO_2 if heated, but without decomposition: 2\,NaHCO_3 + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3 + Na_2CO_3 For ionic: 2\,HCO_3^- + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3 (balanced).

Explanation

1. Identify reaction type <br /> This is an acid-base reaction where bicarbonate reacts with magnesium hydroxide to form water and magnesium carbonate. <br /><br />2. Balance magnesium and carbonate <br /> One $Mg(OH)_2$ reacts with two $HCO_3^-$ because $Mg(OH)_2$ has two OH⁻ groups. <br /><br />3. Balance hydrogen and oxygen <br /> Each $HCO_3$ provides one H to form water, matching OH⁻ from $Mg(OH)_2$. <br /><br />4. Final balanced equation <br /> $2\,HCO_3^- + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3 + CO_2$ if heated, but without decomposition: <br />$2\,NaHCO_3 + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3 + Na_2CO_3$ <br />For ionic: $2\,HCO_3^- + Mg(OH)_2 \rightarrow 2\,H_2O + MgCO_3$ (balanced).
Click to rate:

Similar Questions