QuestionAugust 25, 2025

Answer the following questions. Show how you worked out your answer 1. How many grams make 1 mol of the following? a MgCO_(3) b Na_(3)PO_(4) C_(6)H_(6)MgO_(7)

Answer the following questions. Show how you worked out your answer 1. How many grams make 1 mol of the following? a MgCO_(3) b Na_(3)PO_(4) C_(6)H_(6)MgO_(7)
Answer the following questions. Show how you worked out your answer
1. How many grams make 1 mol of the following?
a MgCO_(3)
b Na_(3)PO_(4)
C_(6)H_(6)MgO_(7)

Solution
4.1(179 votes)

Answer

a. 84.32 g/mol ### b. 163.94 g/mol ### c. 214.41 g/mol Explanation 1. Calculate molar mass of MgCO_{3} Molar mass = sum of atomic masses. Mg = 24.31 g/mol, C = 12.01 g/mol, O = 16.00 g/mol. MgCO_{3} = 24.31 + 12.01 + (3 × 16.00) = 84.32 g/mol. 2. Calculate molar mass of Na_{3}PO_{4} Molar mass = sum of atomic masses. Na = 22.99 g/mol, P = 30.97 g/mol, O = 16.00 g/mol. Na_{3}PO_{4} = (3 × 22.99) + 30.97 + (4 × 16.00) = 163.94 g/mol. 3. Calculate molar mass of C_{6}H_{6}MgO_{7} Molar mass = sum of atomic masses. C = 12.01 g/mol, H = 1.01 g/mol, Mg = 24.31 g/mol, O = 16.00 g/mol. C_{6}H_{6}MgO_{7} = (6 × 12.01) + (6 × 1.01) + 24.31 + (7 × 16.00) = 214.41 g/mol.

Explanation

1. Calculate molar mass of $MgCO_{3}$<br /> Molar mass = sum of atomic masses. Mg = 24.31 g/mol, C = 12.01 g/mol, O = 16.00 g/mol. $MgCO_{3}$ = 24.31 + 12.01 + (3 × 16.00) = 84.32 g/mol.<br /><br />2. Calculate molar mass of $Na_{3}PO_{4}$<br /> Molar mass = sum of atomic masses. Na = 22.99 g/mol, P = 30.97 g/mol, O = 16.00 g/mol. $Na_{3}PO_{4}$ = (3 × 22.99) + 30.97 + (4 × 16.00) = 163.94 g/mol.<br /><br />3. Calculate molar mass of $C_{6}H_{6}MgO_{7}$<br /> Molar mass = sum of atomic masses. C = 12.01 g/mol, H = 1.01 g/mol, Mg = 24.31 g/mol, O = 16.00 g/mol. $C_{6}H_{6}MgO_{7}$ = (6 × 12.01) + (6 × 1.01) + 24.31 + (7 × 16.00) = 214.41 g/mol.
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