QuestionJuly 7, 2025

An atomic anion with a charge of -1 has the following electron configuration: [Ne]3s^23p^4 What is the chemical symbol for the ion? How many electrons does the ion have? How many 3p electrons are in the ion? square square square

An atomic anion with a charge of -1 has the following electron configuration: [Ne]3s^23p^4 What is the chemical symbol for the ion? How many electrons does the ion have? How many 3p electrons are in the ion? square square square
An atomic anion with a charge of -1 has the following electron configuration:
[Ne]3s^23p^4
What is the chemical symbol for the ion?
How many electrons does the ion have?
How many 3p electrons are in the ion?
square 
square 
square

Solution
4.5(347 votes)

Answer

S^{-} ### 17 ### 5 Explanation 1. Identify the Element The electron configuration [Ne]3s^{2}3p^{4} corresponds to sulfur (S) in its neutral state. 2. Determine the Ion An atomic anion with a charge of -1 means it has gained one electron. Sulfur gains one electron to become S^{-}. 3. Count Total Electrons Neutral sulfur has 16 electrons. As S^{-}, it has 17 electrons. 4. Count 3p Electrons In the ion S^{-}, there are 5 electrons in the 3p orbital.

Explanation

1. Identify the Element<br /> The electron configuration $[Ne]3s^{2}3p^{4}$ corresponds to sulfur (S) in its neutral state.<br />2. Determine the Ion<br /> An atomic anion with a charge of $-1$ means it has gained one electron. Sulfur gains one electron to become $S^{-}$.<br />3. Count Total Electrons<br /> Neutral sulfur has 16 electrons. As $S^{-}$, it has 17 electrons.<br />4. Count 3p Electrons<br /> In the ion $S^{-}$, there are 5 electrons in the 3p orbital.
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