QuestionAugust 22, 2025

Which of the following numerical expressions gives the number of particles in 2.0 g of Ne? A (6.0times 10^23particles/mol)/(2.0g) A B (6.0times 10^23particles/mol)/(20.18g/mol) C (2.0g)/(20.18g/mol)(6.0times 10^23pal c D

Which of the following numerical expressions gives the number of particles in 2.0 g of Ne? A (6.0times 10^23particles/mol)/(2.0g) A B (6.0times 10^23particles/mol)/(20.18g/mol) C (2.0g)/(20.18g/mol)(6.0times 10^23pal c D
Which of the following numerical expressions gives the number of particles in 2.0 g of Ne? A (6.0times 10^23particles/mol)/(2.0g) A B (6.0times 10^23particles/mol)/(20.18g/mol) C (2.0g)/(20.18g/mol)(6.0times 10^23pal c D

Solution
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Answer

C \frac {2.0g}{20.18g/mol}(6.0\times 10^{23}) Explanation 1. Identify the formula for number of particles Use **N = \frac{m}{M} \times N_A**, where N is the number of particles, m is mass, M is molar mass, and N_A is Avogadro's number (6.0 \times 10^{23} particles/mol). 2. Calculate using given values For Ne, M = 20.18 g/mol. Substitute m = 2.0 g, M = 20.18 g/mol, and N_A = 6.0 \times 10^{23} particles/mol into the formula.

Explanation

1. Identify the formula for number of particles<br /> Use **$N = \frac{m}{M} \times N_A$**, where $N$ is the number of particles, $m$ is mass, $M$ is molar mass, and $N_A$ is Avogadro's number ($6.0 \times 10^{23}$ particles/mol).<br />2. Calculate using given values<br /> For Ne, $M = 20.18$ g/mol. Substitute $m = 2.0$ g, $M = 20.18$ g/mol, and $N_A = 6.0 \times 10^{23}$ particles/mol into the formula.
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